2016-06-20 19 views
0

我不知道如何獲得一個'或'conditon數據在一個belongsstomany表。我有一張課桌,導師桌和一張學生桌。我爲firstname傳遞一個變量。例如,如果我通過'fred'這個名字,那麼我想讓所有的學生和導師的名字都是'fred'。 我嘗試了一個匹配子句,但是減少了來自主模型的數據,因此無法正確。我使用的地方,但沒有工作,因爲我相信我不能用於這種屬於自己的關係。如何做到這一點請如何使用查找與'或'條件爲belongsToMany,belongsTo表

查詢得到了這列未找到:1054未知列「Students.first_name」在「where子句」

///lesson model 
    $this->belongsTo('Tutors', [ 
      'foreignKey' => 'tutor_id', 
      'joinType' => 'LEFT' 
     ]); 
$this->belongsToMany('Students', [ 
      'foreignKey' => 'lesson_id', 
      'targetForeignKey' => 'student_id', 
      'joinTable' => 'lessons_students' 
     ]); 


$query3 = $this->find() 
       ->contain(['Tutors','Subjects', 'TutoringTypes','Terms','Students']) 
       ->select(['Lessons.id','Lessons.lesson_date','Tutors.id','Tutors.first_name','Tutors.last_name', 
       // 'Students.id','Students.first_name','Students.last_name', 
        'Subjects.name','TutoringTypes.value'])  
       ->where(['Lessons.lesson_date >' => $a3 , 'Tutors.first_name like' => '%'.$firstname.'%', 
        'Tutors.last_name like' => '%'.$lastname.'%' ]) 
       ->orWhere(['Students.first_name like' => '%'.$firstname.'%' ]) 
       ->order(['Lessons.lesson_date' => 'ASC']) 
       ->hydrate(true); 

    /* 
      $query3->matching('Students', function ($q) use ($firstname,$lastname) { 

       return $q 
        // ->select(['Students.id','Students.first_name','Students.last_name']) 
        ->where(['Students.first_name like' =>'%'.$firstname.'%','Students.last_name like' =>'%'.$lastname.'%', ]); 
       }); 
      */ 
       return $query3; 


    SELECT 
     Lessons.id AS `Lessons__id`, 
     Lessons.lesson_date AS `Lessons__lesson_date`, 
     Tutors.id AS `Tutors__id`, 
     Tutors.first_name AS `Tutors__first_name`, 
     Tutors.last_name AS `Tutors__last_name`, 
     Subjects.name AS `Subjects__name`, 
     TutoringTypes.value AS `TutoringTypes__value` 
    FROM 
     lessons Lessons 
     LEFT JOIN tutors Tutors ON Tutors.id = (Lessons.tutor_id) 
     LEFT JOIN subjects Subjects ON Subjects.id = (Lessons.subject_id) 
     LEFT JOIN tutoring_types TutoringTypes ON TutoringTypes.id = (Lessons.tutoring_type_id) 
     LEFT JOIN terms Terms ON Terms.id = (Lessons.term_id) 
    WHERE 
     (
     Students.first_name like '%fred%' 
     OR (
      Lessons.lesson_date > '2016-01-28' 
      AND Tutors.first_name like '%fred%' 
      AND Tutors.last_name like '%%' 
     ) 
    ) 
    ORDER BY 
     Lessons.lesson_date ASC 
    LIMIT 
     20 OFFSET 0 

    http://book.cakephp.org/3.0/en/orm/query-builder.html 


    //generated query from the below answer 
    SELECT 
     Lessons.id AS `Lessons__id`, 
     Lessons.lesson_date AS `Lessons__lesson_date`, 
     Tutors.id AS `Tutors__id`, 
     Tutors.first_name AS `Tutors__first_name`, 
     Tutors.last_name AS `Tutors__last_name`, 
     Subjects.name AS `Subjects__name`, 
     TutoringTypes.value AS `TutoringTypes__value` 
    FROM 
     lessons Lessons 
     LEFT JOIN tutors Tutors ON Tutors.id = (Lessons.tutor_id) 
     LEFT JOIN subjects Subjects ON Subjects.id = (Lessons.subject_id) 
     LEFT JOIN tutoring_types TutoringTypes ON TutoringTypes.id = (Lessons.tutoring_type_id) 
     LEFT JOIN terms Terms ON Terms.id = (Lessons.term_id) 
    WHERE 
     (
     Lessons.lesson_date > '2016-01-28' 
     AND (
      Students.first_name like '%%' 
      OR Tutors.first_name like '%%' 
      OR Tutors.last_name like '%%' 
     ) 
    ) 
    ORDER BY 
     Lessons.lesson_date ASC 
    LIMIT 
     20 OFFSET 0 
+2

從提供給你所需數據的sql開始。問題標題似乎與您的實際問題很少有關。 – AD7six

+0

由於belongsToMany關係,「匹配」查詢應該是這裏的方法。你有什麼問題?您可能希望查看'autoFields'以在結果集中包含其他數據。 –

+0

我試過匹配的查詢,但是減少了行數。我需要兩個表中名稱相同的行。在原來的文章中有一個匹配的條款註釋掉了。如果還有其他方法,請讓我看看,因爲我不知道該怎麼辦 – ajt

回答

0

我通過除去學生belongstomany關係找到了答案,把它改成了哈曼。這是一個相當大的變化,但這種歸屬感的關係有時會讓人頭疼。

$query3 = $this->find() 
       ->contain(['Tutors','Subjects', 'TutoringTypes','Terms','Students']) 
       ->select(['Lessons.id','Lessons.lesson_date','Tutors.id','Tutors.first_name','Tutors.last_name', 
        'Students.id','Students.first_name','Students.last_name', 
        'Subjects.name','TutoringTypes.value'])  
       ->where(['Lessons.lesson_date >' => $a3 , 
        'OR' => [[ 'Tutors.first_name like' => '%'.$firstname.'%', 'Tutors.last_name like' => '%'.$lastname.'%'], 
          ['Students.first_name like' => '%'.$firstname.'%', 'Students.last_name like' => '%'.$lastname.'%']] 
       ]) 
       ->order(['Lessons.lesson_date' => 'ASC']) 
       ->hydrate(true);