在Powershell中搜索xmls

Question

如何使用powershell查找此XML中的路徑？例如，我需要找到應用程序/名的路徑= PSTest，環境/名稱= DEMO

下面是示例XML：

<Applications> 
     <Application> 
      <Name>PSTest</Name> 
      <Environment> 
       <Name>DEMO</Name> 
       <BuildPath>C:\TEST\TEST</BuildPath> 
       <Path>C:\TEST\DEMO\PSTest|C:\TEST\DEMO1\PSTest</Path> 
       <BackupPath>C:\TEST\Backup</BackupPath> 
      </Environment> 
      <Environment> 
       <Name>PROD</Name> 
       <BuildPath>C:\TEST\DEMO</BuildPath> 
       <Path>C:\TEST\PROD\PSTest|C:\TEST\PROD1\PSTest</Path> 
       <BackupPath>C:\TEST\Backup\PROD</BackupPath> 
      </Environment> 
     </Application> 
     <Application> 
      <Name>PSTestTwo</Name> 
      <Environment> 
       <Name>DEMO</Name> 
       <BuildPath>C:\TEST\TEST</BuildPath> 
       <Path>C:\TEST\DEMO\PSTestTwo|C:\TEST\DEMO1\PSTestTwo</Path> 
       <BackupPath>C:\TEST\Backup</BackupPath> 
      </Environment> 
      <Environment> 
       <Name>PROD</Name> 
       <BuildPath>C:\TEST\DEMO</BuildPath> 
       <Path>C:\TEST\PROD\PSTestTwo|C:\TEST\PROD1\PSTestTwo</Path> 
       <BackupPath>C:\TEST\Backup\PROD</BackupPath> 
      </Environment> 
     </Application> 
    </Applications> 

Answer 1

您可以使用XPath字符串以查找和選擇節點：

$oXml = [Xml](Get-Content "infile.xml" | Out-String) 
$sXPath = '//Application[Name = "PSTest"]/Environment[Name = "DEMO"]' 
$sPath = ($oXml.SelectSingleNode($sXPath)).Path 
$sPath 

請記住，與PowerShell本身不同，XPath區分大小寫。