我需要接受電子郵件驗證正則表達式中@
字符之前的_
字符。我沒有寫這個代碼,而且我在理解和修改它時遇到了一些困難。我需要接受正則表達式電子郵件驗證中的下劃線字符「_」
例子:
function($){
$.fn.validationEngineLanguage = function(){
};
$.validationEngineLanguage = {
newLang: function(){
$.validationEngineLanguage.allRules = {
...
"email": {
// Shamelessly lifted from Scott Gonzalez via the Bassistance Validation plugin http://projects.scottsplayground.com/email_address_validation/
"regex": /^((([a-z]|\d|[!#\$%&'\*\+\-\/=\?\^_`{\|}~]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])+(\.([a-z]|\d|[!#\$%&'\*\+\-\/=\?\^_`{\|}~]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])+)*)|((\x22)((((\x20|\x09)*(\x0d\x0a))?(\x20|\x09)+)?(([\x01-\x08\x0b\x0c\x0e-\x1f\x7f]|\x21|[\x23-\x5b]|[\x5d-\x7e]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(\\([\x01-\x09\x0b\x0c\x0d-\x7f]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF]))))*(((\x20|\x09)*(\x0d\x0a))?(\x20|\x09)+)?(\x22)))@((([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])*([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])))\.)+(([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])*([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])))\.?$/i,
"alertText": "* Correo inválido"
},
...
};
}
};
$.validationEngineLanguage.newLang();
})(jQuery);
[電子郵件地址非常難以驗證](http://stackoverflow.com/questions/201323/using-a-regular-表達到驗證-AN-電子郵件地址)。您最好的解決方案不是使用正則表達式,而是添加服務器端代碼來向該地址發送確認電子郵件。 – Blazemonger
那麼是否需要有'_',或者只有在_之前有'_'? – lintmouse
如果你只是想確保'@'後面沒有'_',那麼可以用這個:'@ [^ _] + $'離開。 – lintmouse