php而關閉另一個ID的行

Question

我有我的PHP，打印出一堆mysql數據庫的行。它看起來像這樣：

http://prntscr.com/7dafb9

如果我點擊close ticket頂行，它會永遠關閉最後一個行ID，因爲它是最後一個ID放排，我不知道這有什麼錯我的代碼。那就是：

<?php 
 
    $sql = "SELECT id,name,server,issue,title,open FROM tickets WHERE open='1' ORDER by time"; 
 
    $result = $configconn->query($sql); 
 
\t \t \t \t \t \t \t \t 
 
    if ($result->num_rows > 0) { 
 
     while($row = $result->fetch_assoc()) { 
 
     $ticketid = $row["id"]; 
 
     $ticketopen = $row["open"]; 
 
     $ticketserver = $row["server"]; 
 
     $ticketissue = $row["issue"]; 
 
     $tickettitle = $row["title"]; 
 
     $ticketname = $row["name"]; 
 

 
     if($ticketopen == 1) { 
 
      $open = '<span class="label label-success label-mini">Open ID:'.$ticketid.'</span>'; 
 
     } else { 
 
      $open = '<span class="label label-danger label-mini">Closed ID:'.$ticketid.'</span>'; 
 
     } 
 

 
     echo ' <tr> 
 
      <td>'.$open.'</td> 
 
      <td class="hidden-phone">'.$ticketissue.'</td> 
 
      <td>'.$tickettitle.' </td> 
 
      <td><span class="label label-info label-mini">'.$ticketserver.'</span></td> 
 
      <td>'.$ticketname.' </td> 
 

 
      <form action="openedtickets.php" method="POST"> 
 
      <td> \t \t \t \t \t \t \t 
 
       <button class="btn btn-danger btn-xs" type="submit" name="submit" value="Register">Close Ticket</button> \t \t \t \t \t \t \t 
 
      </td> 
 
      </form> 
 
     </tr>'; 
 
\t \t \t \t \t \t \t 
 
     } 
 
    } else { 
 
     Echo '<center><div class="alert alert-success">There are no open Tickets!</div></center>'; 
 
    } 
 
    ?> 
 

 
    <?php 
 

 
    if(isset($_POST['submit'])){ 
 
     if($_SESSION['power'] >= 1){ 
 
     $sql = "UPDATE tickets SET open='0' WHERE id='$ticketid'"; 
 
     if (mysqli_query($configconn, $sql)) { 
 
      $sollved = $_SESSION['ticketssolved'] + 1; \t 
 
      $sql2 = "UPDATE users SET ticketssolved='$sollved' WHERE user='$user'"; \t 
 
      mysqli_query($configconn, $sql2); 
 
\t \t \t \t \t \t \t \t \t \t \t 
 
      $closedby = $_SESSION['username']; \t 
 
      $sql3 = "UPDATE tickets SET closedticket='$closedby' WHERE id='$ticketid'"; \t 
 
      mysqli_query($configconn, $sql3); 
 
      header("Location: openedtickets.php"); 
 

 
     } else { 
 

 
      Echo '<center><div class="alert alert-danger">Ticket ID:'.$ticketid.' Failed to Close!</div></center>'; 
 
\t \t \t \t \t \t \t \t \t \t \t 
 
     } 
 
     } else { 
 

 
     Echo '<center><div class="alert alert-danger">Sorry you need to be Trial Mod or Higher!</div></center>'; 
 

 
    } 
 
\t \t \t \t \t \t \t \t \t 
 
    } 
 
?>

Answer 1

<form action="openedtickets.php" method="POST"> 
    <td> 
     <input type='hidden' name='ticketid' value="<?php echo $ticketid; ?>" /> 
     <button class="btn btn-danger btn-xs" type="submit" name="submit" value="Register">Close Ticket</button> 

    </td> 
</form>