美麗的湯和uTidy

我想傳遞的utidy到美麗的湯，結果，鼻翼：美麗的湯和uTidy

page = urllib2.urlopen(url) 
options = dict(output_xhtml=1,add_xml_decl=0,indent=1,tidy_mark=0) 
cleaned_html = tidy.parseString(page.read(), **options) 
soup = BeautifulSoup(cleaned_html)

運行時，下面的錯誤結果：

Traceback (most recent call last): 
    File "soup.py", line 34, in <module> 
    soup = BeautifulSoup(cleaned_html) 
    File "/var/lib/python-support/python2.6/BeautifulSoup.py", line 1499, in __init__ 
    BeautifulStoneSoup.__init__(self, *args, **kwargs) 
    File "/var/lib/python-support/python2.6/BeautifulSoup.py", line 1230, in __init__ 
    self._feed(isHTML=isHTML) 
    File "/var/lib/python-support/python2.6/BeautifulSoup.py", line 1245, in _feed 
    smartQuotesTo=self.smartQuotesTo, isHTML=isHTML) 
    File "/var/lib/python-support/python2.6/BeautifulSoup.py", line 1751, in __init__ 
    self._detectEncoding(markup, isHTML) 
    File "/var/lib/python-support/python2.6/BeautifulSoup.py", line 1899, in _detectEncoding 
    xml_encoding_match = re.compile(xml_encoding_re).match(xml_data) 
TypeError: expected string or buffer

我收集utidy返回的XML文檔而BeautifulSoup需要一個字符串。有沒有一種方法可以轉換clean_html？或者我做錯了，應該採取不同的方法？

來源

2009-05-20 jldugger

只是將str()換成cleaned_html 纔會傳遞給BeautifulSoup。

來源

2009-05-20 06:11:05

將傳遞給BeautifulSoup的值轉換爲字符串。在你的情況下，做以下編輯到最後一行：

soup = BeautifulSoup(str(cleaned_html))

來源

2015-09-16 15:39:29

美麗的湯和uTidy

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