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我想從Twitter API獲取Oauth request_token。 但是，當我運行的代碼，它是輸出「未經授權」，雖然我是一個授權用戶。 以下是輸出：嘗試從Twitter API獲取Oauth request_token時出現「未經授權」錯誤
"parameter_string=oauth_consumer_key=MlyUxiF1ihXIymYIPWZCA&oauth_nonce=7ee1983904884d45b723f6cc50306617&oauth_signature_method=HMAC-SHA1&oauth_timestamp=1385127328&oauth_version=1.0
signature_base_string=POST&https%3A%2F%2Fapi.twitter.com%2Foauth%2Frequest_token&oauth_consumer_key%3DMlyUxiF1ihXIymYIPWZCA%26oauth_nonce%3D7ee1983904884d45b723f6cc50306617%26oauth_signature_method%3DHMAC-SHA1%26oauth_timestamp%3D1385127328%26oauth_version%3D1.0
oauth_signature=%2FOnHRfoRKyxPd9KG%2BA0HlFvE6yg%3D
authorization_header_string=OAuth oauth_consumer_key="MlyUxiF1ihXIymYIPWZCA",oauth_signature_method="HMAC-SHA1",oauth_timestamp="1385127328",oauth_nonce="7ee1983904884d45b723f6cc50306617",oauth_version="1.0",oauth_signature="%2FOnHRfoRKyxPd9KG%2BA0HlFvE6yg%3D"
log4j:WARN No appenders could be found for logger (org.apache.http.impl.conn.BasicClientConnectionManager).
log4j:WARN Please initialize the log4j system properly.
log4j:WARN See http://logging.apache.org/log4j/1.2/faq.html#noconfig for more info.
Unauthorized
"
這裏是我的全碼：
import java.io.IOException;
import java.io.UnsupportedEncodingException;
import java.net.URLEncoder;
import java.security.GeneralSecurityException;
import java.util.Date;
import java.util.UUID;
import javax.crypto.Mac;
import javax.crypto.SecretKey;
import javax.crypto.spec.SecretKeySpec;
import org.apache.commons.codec.binary.Base64;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.ResponseHandler;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.BasicResponseHandler;
import org.apache.http.impl.client.DefaultHttpClient;
public class TwitterConnection {
public static void main(String args[]) throws UnsupportedEncodingException {
// System.out.println(System.getProperty("java.classpath"));
String oauth_signature_method = "HMAC-SHA1";
String oauth_consumer_key = "MlyUxiF1ihXIymYIPWZCA";
String uuid_string = UUID.randomUUID().toString();
uuid_string = uuid_string.replaceAll("-", "");
String oauth_nonce = uuid_string; // any relatively random alphanumeric
// string will work here. I used
// UUID minus "-" signs
long timestamp_at_entry = new Date().getTime();
String oauth_timestamp = (new Long(timestamp_at_entry/1000))
.toString(); // get current time in milliseconds, then divide by
// 1000 to get seconds
// I'm not using a callback value. Otherwise, you'd need to include it
// in the parameter string like the example above
// the parameter string must be in alphabetical order
String parameter_string = "oauth_consumer_key=" + oauth_consumer_key
+ "&oauth_nonce=" + oauth_nonce + "&oauth_signature_method="
+ oauth_signature_method + "&oauth_timestamp="
+ oauth_timestamp + "&oauth_version=1.0";
System.out.println("parameter_string=" + parameter_string);
String signature_base_string = "POST&https%3A%2F%2Fapi.twitter.com%2Foauth%2Frequest_token&"
+ URLEncoder.encode(parameter_string, "UTF-8");
System.out.println("signature_base_string=" + signature_base_string);
String oauth_signature = "";
try {
oauth_signature = computeSignature(signature_base_string,
"122595245-sPcfsJO3GRkJpjzgFLZ918OaHkxeSmwYg9WDn23Z"); // note
// the
// &
// at
// the
// end.
// Normally
// the
// user
// access_token
// would
// go
// here,
// but
// we
// don't
// know
// it
// yet
// for
// request_token
System.out.println("oauth_signature="
+ URLEncoder.encode(oauth_signature, "UTF-8"));
} catch (GeneralSecurityException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
String authorization_header_string = "OAuth oauth_consumer_key=\""
+ oauth_consumer_key
+ "\",oauth_signature_method=\"HMAC-SHA1\",oauth_timestamp=\"" +
oauth_timestamp + "\",oauth_nonce=\"" + oauth_nonce
+ "\",oauth_version=\"1.0\",oauth_signature=\""
+ URLEncoder.encode(oauth_signature, "UTF-8") + "\"";
System.out.println("authorization_header_string="
+ authorization_header_string);
String oauth_token = "";
HttpClient httpclient = new DefaultHttpClient();
try {
// HttpParams params = new SyncBasicHttpParams();
// HttpProtocolParams.setVersion(params, HttpVersion.HTTP_1_1);
// HttpProtocolParams.setContentCharset(params, "UTF-8");
// HttpProtocolParams.setUserAgent(params, "HttpCore/1.1");
// HttpProtocolParams.setUseExpectContinue(params, false);
//
// HttpProcessor httpproc = new ImmutableHttpProcessor(
// new HttpRequestInterceptor[] {
// // Required protocol interceptors
// new RequestContent(), new RequestTargetHost(),
// // Recommended protocol interceptors
// new RequestConnControl(), new RequestUserAgent(),
// new RequestExpectContinue() });
//
// HttpRequestExecutor httpexecutor = new HttpRequestExecutor();
// HttpContext context = new BasicHttpContext(null);
// HttpHost host = new HttpHost(
// "https://api.twitter.com/oauth/request_token", 443); // use
// // 80
// // if
// // you
// // want
// // regular
// // HTTP
// // (not
// // HTTPS)
// DefaultHttpClientConnection conn = new DefaultHttpClientConnection();
//
// context.setAttribute(ExecutionContext.HTTP_CONNECTION, conn);
// context.setAttribute(ExecutionContext.HTTP_TARGET_HOST, host);
//
// // initialize the HTTPS connection
// SSLContext sslcontext = SSLContext.getInstance("TLS");
// sslcontext.init(null, null, null);
// SSLSocketFactory ssf = sslcontext.getSocketFactory();
// for HTTP, use this instead of the above.
// Socket socket = new Socket(host.getHostName(), host.getPort());
// conn.bind(socket, params);
// BasicHttpEntityEnclosingRequest request2 = new BasicHttpEntityEnclosingRequest(
// "POST", "https://api.twitter.com/oauth/request_token");
// request2.setEntity(new StringEntity("",
// "application/x-www-form-urlencoded", "UTF-8"));
// request2.setParams(params);
// request2.addHeader("Authorization", authorization_header_string); // this
// // is
// // where
// // we're
// // adding
// // that
// // required
// // "Authorization: BLAH"
// // header.
// httpexecutor.preProcess(request2, httpproc, context);
// HttpResponse response2 = httpexecutor.execute(request2, conn,
// context);
// //
HttpPost httppost = new
HttpPost("https://api.twitter.com/oauth/request_token");
httppost.setHeader("Authorization",authorization_header_string);
ResponseHandler<String> responseHandler = new
BasicResponseHandler();
String responseBody = httpclient.execute(httppost,
responseHandler);
oauth_token =
responseBody.substring(responseBody.indexOf("oauth_token=") + 12,
responseBody.indexOf("&oauth_token_secret="));
System.out.println(responseBody);
}
catch (ClientProtocolException cpe) {
System.out.println(cpe.getMessage());
}
catch (IOException ioe) {
System.out.println(ioe.getMessage());
}
finally {
httpclient.getConnectionManager().shutdown();
}
}
private static String computeSignature(String baseString, String keyString)
throws GeneralSecurityException, UnsupportedEncodingException {
SecretKey secretKey = null;
byte[] keyBytes = keyString.getBytes();
secretKey = new SecretKeySpec(keyBytes, "HmacSHA1");
Mac mac = Mac.getInstance("HmacSHA1");
mac.init(secretKey);
byte[] text = baseString.getBytes();
return new String(Base64.encodeBase64(mac.doFinal(text))).trim();
}
}
我想知道，我該如何解決這個問題，並得到了request_token。
嗨，我使用的路標如你所說，但是當我寫的程序，並給我申請的相應憑證，它是失敗說 異常線程「main」 oauth.signpost.exception.OAuthExpectationFailedException：請求令牌或令牌祕密未在服務器回覆中設置。您使用的服務提供商可能是越野車。 \t在oauth.signpost.basic.DefaultOAuthProvider.retrieveToken（DefaultOAuthProvider.java:138） \t在oauth.signpost.basic.DefaultOAuthProvider.retrieveRequestToken（DefaultOAuthProvider.java:66）在Main.main（Main.java:30）」想知道我是否在這裏失去了一些東西。 –