從文本文件讀入矢量

Question

我很難看出爲什麼我的代碼不起作用。出現問題的部分是當我將文本文件中的值傳遞給我的等級變量時。我不明白爲什麼這是錯的。無論如何，我的代碼的其他一切都很好，但我還是把它包括在內了。

string fileName; 

cout << "Program that takes data from file and calculate\nmean and standard deviation and put it in file out.txt\n"; 
cout << "Enter the input file name "; 
cin >> fileName; 
    double grade; 
ifstream inData; 

inData.open(fileName.c_str()); 

// Declare vector<double> vecx 
vector<double> vecx; 
// read data from input file to vector vecx, 
while(inData >> grade) 
{ 
    vecx.push_back(grade); 
} 


inData.close(); 
// keep track how many elements you read from file 
// When you done with reading from file, close stream inData 

這裏是完整的代碼，如果你有興趣。

#include <iostream> 
#include <fstream> 
#include <vector> 
#include <cmath> 

using namespace std; 

int main() 
{ 
    string fileName; 

    cout << "Program that takes data from file and calculate\nmean and standard deviation and put it in file out.txt\n"; 
    cout << "Enter the input file name "; 
    cin >> fileName; 
     double grade; 
    ifstream inData; 

    inData.open(fileName.c_str()); 

    // Declare vector<double> vecx 
    vector<double> vecx; 
    // read data from input file to vector vecx, 
    while(inData >> grade) 
    { 
     vecx.push_back(grade); 
    } 


    inData.close(); 
    // keep track how many elements you read from file 
    // When you done with reading from file, close stream inData 

    // read element by element in vector vecx and calculate sum; 
    double sum=0; 
    double average; 
    for (int i=0; i < vecx.size(); i++) 
     sum=sum+vecx[i]; 

    average=sum/(vecx.size()); 
    // sum divide by number of elements to find mean(average) 

    //again read element by element and calculate 
    //square of difference between element and mean 
    //calculate sum of squares of differences 
    //divide by number of elements and 
    //take square root - you got the standard deviation 

    sum=0; 
    double variance, stdev; 
    for (int i=0; i < vecx.size(); i++) 
     sum=sum+(vecx[i]-average*vecx[i]-average); 

    variance=sum/(vecx.size()); 
    stdev=sqrt(variance); 

    //open output stream 
    ofstream outData; 
    outData.open("out.txt"); 
    //output mean and standard deviation 

    cout << "Average is " << average << endl; 
    cout << "Standard deviation is " << stdev << endl; 

    //close stream 
    outData.close(); 
} 

我感覺自己就像沒有看到爲什麼這是不工作...我應該能想出解決辦法，但我不是白癡。

Answer 1

C++遵循先例的正常數學順序。

這條線：

sum=sum+(vecx[i]-average*vecx[i]-average); 

看起來不正確。乘法，所以它計算這個減法之前發生：

sum=sum+((vecx[i]-(average*vecx[i]))-average); 

但想必你的意思是這樣的：

sum=sum+((vecx[i]-average)*(vecx[i]-average)); 

你可能有興趣看到the full list of precedence ordering。

Answer 2

您從不將數據寫入您的文件。使用您的ofstream outData而不是std::cout。否則，你只是將你的輸出發送到控制檯。

//open output stream 
ofstream outData; 
outData.open("out.txt"); 
//output mean and standard deviation 

outData << "Average is " << average << endl; 
outData << "Standard deviation is " << stdev << endl; 

//close stream 
outData.close();