用java正則表達式讀取文本文件來匹配多個模式，我想

Question

代碼：

import java.io.*; 
import java.util.regex.*; 
public class All { 
    public static void main(String[] args) { 
     String input = "IT&&faculty.*"; 
     try { 
      FileInputStream fstream = new FileInputStream("uu.txt"); 
      DataInputStream in = new DataInputStream(fstream); 
      BufferedReader br = new BufferedReader(new InputStreamReader(in)); 
      String strLine; 
      while ((strLine = br.readLine()) != null) { 
       if (Pattern.matches(input, strLine)) { 
        Pattern p = Pattern.compile("'(.*?)'"); 
        Matcher m = p.matcher(strLine); 
        while (m.find()) { 
         String b = m.group(1); 
         String c = b.toString() + ".*"; 
         System.out.println(b); 

         if (Pattern.matches(c, strLine)) { 
          Pattern pat = Pattern.compile("<(.*?)>"); 
          Matcher mat = pat.matcher(strLine); 
          while (mat.find()) { 
           System.out.println(m.group(1)); 

          } 
         } else { 
          System.out.println("Not found"); 
         } 
        } 
       } 
      } 
     } catch (Exception e) { 
      System.err.println("Error: " + e.getMessage()); 
     } 
    } 
} 

我的文本文件的內容是： \表示它是一個換行符

輸入文件：

IT&&faculty('Mousum handique'|'Abhijit biswas'|'Arnab paul'|'Bhagaban swain') 
Mousum handique(designation|address|phone number|'IT Assistant   professor'|<AUS staff quaters>|#5566778899#) 
Abhijit biswas(designation|address|phone number|'IT Assistant professor'|<AUW staff quaters>|#5566778891#) 
Arnab paul(designation|address|phone number|'IT Assistant professor'|<AUE staff quaters>|#5566778890#) 
Bhagaban swain(designation|address|phone number|'IT Assistant professor'|<AUW staff quarters>|#5566778892#) 

它給出的結果 -

Mousum handique 
Not found 
Abhijit Biswas 
Not found 
Arnab Paul 
Not found 
Bhagaban swain 
Not found 

而我想要的結果是：

Mousum handique 
AUS staff quaters 
Abhijit Biswas 
AUW staff quaters 
Arnab Paul 
AUE staff quaters 
Bhagaban swain 
AUW staff quaters 

這是第一次比賽後，我想，當它得到Mousu​​m handique從文件應該再次搜索該文件，並在那裏得到這樣一行Mousu​​m handique它應該打印任何內<>對應的行。請參閱我的文本文件的數據來理解我的問題。對不起，如果我的問題似乎很愚蠢，但我嘗試了很多！

Answer 1

你並不需要使用string.matches方法只使用Patttern和匹配器類在同一行本身<>之間提取這是在該行的開頭名稱，也是內容。

String s = "IT&&faculty('Mousum handique'|'Abhijit biswas'|'Arnab paul'|'Bhagaban swain')\n" + 
     " Mousum handique(designation|address|phone number|'IT Assistant   professor'|<AUS staff quaters>|#5566778899#)\n" + 
     " Abhijit biswas(designation|address|phone number|'IT Assistant professor'|<AUW staff quaters>|#5566778891#)\n" + 
     "Arnab paul(designation|address|phone number|'IT Assistant professor'|<AUE staff quaters>|#5566778890#)\n" + 
     "Bhagaban swain(designation|address|phone number|'IT Assistant professor'|<AUW staff quarters>|#5566778892#)"; 
Matcher m = Pattern.compile("(?m)^\\s*([^\\(]+)\\([^\\)]*\\|<([^>]*)>[^\\)]*\\)").matcher(s); 
while(m.find()) 
{ 
    System.out.println(m.group(1)); 
    System.out.println(m.group(2)); 
} 

輸出：

Mousum handique 
AUS staff quaters 
Abhijit biswas 
AUW staff quaters 
Arnab paul 
AUE staff quaters 
Bhagaban swain 
AUW staff quarters 

DEMO

更新：

使用此正則表達式也獲得ID號。

String s = "IT&&faculty('Mousum handique'|'Abhijit biswas'|'Arnab 
paul'|'Bhagaban swain')\n" + 
       " Mousum handique(designation|address|phone number|'IT Assistant   professor'|<AUS staff quaters>|#5566778899#)\n" + 
       " Abhijit biswas(designation|address|phone number|'IT Assistant professor'|<AUW staff quaters>|#5566778891#)\n" + 
       "Arnab paul(designation|address|phone number|'IT Assistant professor'|<AUE staff quaters>|#5566778890#)\n" + 
       "Bhagaban swain(designation|address|phone number|'IT Assistant professor'|<AUW staff quarters>|#5566778892#)"; 
     Matcher m = Pattern.compile("(?m)^\\s*([^\\(]+)\\([^\\)]*\\|<([^>]*)>[^\\)]*\\|#([^#]*)#[^\\)]*\\)").matcher(s); 
     while(m.find()) 
     { 
      System.out.println(m.group(1)); 
      System.out.println(m.group(2)); 
      System.out.println(m.group(3)); 
     } 

輸出：

Mousum handique 
AUS staff quaters 
5566778899 
Abhijit biswas 
AUW staff quaters 
5566778891 
Arnab paul 
AUE staff quaters 
5566778890 
Bhagaban swain 
AUW staff quarters 
5566778892 

Answer 2

一個錯誤是在這裏：

while (mat.find()) { 
    System.out.println(m.group(1)); // <-- you should use mat - not m!!! 
} 

第二個錯誤是在這裏：

if (Pattern.matches(c, strLine)) { 

這if爲n自從字符串c是上一場比賽+「.*」以來輸入。刪除這個條件，它會工作。

固定碼：

... 
    Pattern p = Pattern.compile("'(.*?)'"); 
    Matcher m = p.matcher(strLine); 
    while (m.find()) { 
     String b = m.group(1); 
     System.out.println(b);    
     Pattern pat = Pattern.compile("<(.*?)>"); 
     Matcher mat = pat.matcher(strLine); 
     while (mat.find()) { 
      System.out.println(mat.group(1)); 

     }    
    } 
    ... 

運行此代碼與輸入：

"Abhijit biswas(designation|address|phone number|'IT Assistant professor'|<AUW staff quaters>|#5566778891#) 

輸出：

IT Assistant professor 
AUW staff quaters