我有一所學校計劃我剛剛得到的陣列,我們正在學習散列和老師走了過去陣列的哈希值,但沒有真正陣列哈希我覺得自己像一個AOH是要對我的工作進行更好從長遠來看。現在,我將所有數據都存入單獨的變量,並且我希望將它們存儲到AoH bc中。我的整個時間都有相同的變量,但值會更改。將數據存儲到哈希
什麼程序,是一個日誌分析器,並通過一個巨大的日誌文件分析和所有的數據是,是,是這樣的線路。
IPADDY x x [DATE:TIME -x] "METHOD URL HTTPVERS" STATUSCODE BYTES "REFERER" "USERAGENT"
例如線是
27.112.105.20 - - [09/Oct/2011:07:22:51 -0500] "GET/HTTP/1.1" 200 4886 "-" "Python-urllib/2.4"
現在我得到的所有數據精我只是不真正瞭解如何填充和散列的數組如果有人能幫助我。
這裏是一個更新的代碼,抓取數據並嘗試將其存儲到AoH中。我的文件中的輸出曾經是完美的,就像我現在評論的打印語句一樣。這就是我的輸出文件現在的所有「ARRAY(0x2395df0):HASH(0x23d06e8)」。難道我做錯了什麼?
#!/usr/bin/perl
use strict;
use warnings;
my $j = 0;
my @arrofhash;
my $ipadd;
my $date;
my $time;
my $method;
my $url;
my $httpvers;
my $statuscode;
my $bytes;
my $referer;
my $useragent;
my $dateANDtime;
my ($dummy1, $dummy2, $dummy3);
open (MYFILE, '>>dodoherty.report');
if (@ARGV < 1)
{
printf "\n\tUsage: $0 file word(s)\n\n";
exit 0;
}
for (my $i = 0; $i < @ARGV; ++$i)
{
open(HANDLE, $ARGV[$i]);
while(my $line = <HANDLE>)
{
($ipadd, $dummy1, $dummy2, $dateANDtime, $dummy3, $method, $url, $httpvers, $statuscode, $bytes, $referer, $useragent) = split(/\s/, $line);
$method = substr ($method, 1, length($method));
$httpvers = substr ($httpvers, 0, length($httpvers)-1);
$referer = substr ($referer, 1, length($referer)-2);
$useragent = substr ($useragent, 1, length($useragent)-1);
if (substr ($useragent, length($useragent)-1, length($useragent)) eq '"')
{
chop $useragent;
}
if ($dateANDtime =~ /\[(\S*)\:(\d{2}\:\d{2}\:\d{2})/)
{
$date = $1;
$time = $2;
}
$arrofhash[$i] = {ipadd => $ipadd, date => $date, 'time' => $time, method => $method, url => $url, httpvers => $httpvers, statuscode => $statuscode, bytes => $bytes, referer => $referer, useragent => $useragent};
# print MYFILE "IPADDY :$ipadd\n";
# print MYFILE "METHOD :$method\n";
# print MYFILE "URL :$url\n";
# print MYFILE "HTTPOVERS : $httpvers\n";
# print MYFILE "STATUS CODE: $statuscode\n";
# print MYFILE "BYTES : $bytes\n";
# print MYFILE "REFERER : $referer\n";
# print MYFILE "USERAGENT : $useragent\n";
# print MYFILE "DATE : $date\n";
# print MYFILE "TIME : $time\n\n";
}
}
for (my $j = 0; $j < @arrofhash; ++$j)
{
foreach my $hash (@hashkeys)
{
printf MYFILE "%s: %s\n",$hash, $arrofhash[$j];
}
print MYFILE "\n";
}
close (MYFILE);
哇這看起來更清潔我的唯一想法是我應該有日期和時間作爲單獨的變量,但我相信我可以修復這個正則表達式一點點。 – Trance339 2012-02-29 17:05:42
@ Trance339我建議你事後做處理。例如。 'my($ date,$ time)= split /:/,$ f {dateANDtime},2;'2「是分割的LIMIT參數,它決定了要返回多少個字段。 – TLP 2012-02-29 17:29:12