代碼The string1 outlet from the OptionalListViewController to the UILabel is invalid. Outlets can not be connected to repeating contentnill分配數據標籤(意外地發現零而展開的可選值)
import UIKit
class ListsTableViewCell: UITableViewCell {
override func awakeFromNib() {
super.awakeFromNib()
// Initialization code
}
override func setSelected(selected: Bool, animated: Bool) {
super.setSelected(selected, animated: animated)
// Configure the view for the selected state
}
@IBOutlet weak var string1: UILabel!
@IBOutlet weak var string2: UILabel!
@IBOutlet weak var string3: UILabel!
@IBOutlet weak var string4: UILabel!
@IBOutlet weak var string5: UILabel!
}
var cellyItem = ListsTableViewCell()
override func tableView(tableView: UITableView,
cellForRowAtIndexPath indexPath:
NSIndexPath) -> ListsTableViewCell {
let cell:ListsTableViewCell = tableView.dequeueReusableCellWithIdentifier("Celly", forIndexPath: indexPath) as! ListsTableViewCell
let dic:NSDictionary = _items.objectAtIndex(indexPath.row) as! NSDictionary
print(" Plist:\(dic)")
let str0:NSString = dic["0"]! as! NSString
let str1:NSString = dic["1"]! as! NSString
let str2:NSString = dic["2"]! as! NSString
let str3:NSString = dic["3"]! as! NSString
let str4:NSString = dic["4"]! as! NSString
let str5:NSString = dic["5"]! as! NSString
let str6:NSString = dic["6"]! as! NSString
let str7:NSString = dic["7"]! as! NSString
let str8:NSString = dic["8"]! as! NSString
cellyItem.string1.text = (str0 as String) + (str1 as String)
cellyItem.string2.text = (str2 as String) + (str3 as String)
cellyItem.string3.text = (str4 as String) + (str5 as String)
cellyItem.string4.text = (str6 as String) + (str7 as String)
cellyItem.string5.text = (str4 as String) + (str8 as String)
return cell
}
cellyItem.string1,2,3,4,5的第一部分時 - 收到珍妮
爲什麼會發生這種情況?像所有的權利!這個「str0,1,2,3,4,5,6,7,8」接收數據。也許我需要初始化子類?
第一件事:將每個強制解包值(' !')與安全解包('如果let'),和'else'分支來處理錯誤。 – Moritz
另外:[編輯]你的問題,以便它有正確的代碼佈局(縮進4個空格),並刪除頂部的無用文本。 –
爲什麼你轉換爲NSString,然後轉換爲字符串?你可以直接轉換爲字符串。 – kelin