如何爲Json數據格式生成JsonStringer？

Question

你好，我有一個JSON數據格式可以請人幫我做動態JSONStringer對象此字符串

{"Text":"Hello Simple Text", 
"Files":[{"ContentType":"image/png", 
"Content":"iVBORw0KGgoAAAANSUhEUgAAAR8AAACMCAIAAADKsDpDAAAACXBIWXMAAA7EAAAOxAGVKw4bAAAAB3RJTUUH2wYWDzIB3zSYdQAAAAd0RVh0QXV0aG9yAKmuzEgAAAAMdEVYdERlc2NyaXB0aW9uABMJISMAAAAKdEVYdENvcHlyaWdodACsD8w6AAAADnRFWHRDcmVhdGlvbiB0aW1lADX3DwkAAAAJdEVYdFNvZnR3YXJlAF1w/zoAAAALdEVYdERpc2NsYWltZXIAt8C0jwAAAAh0RVh0V2FybmluZwDAG+aHAAAAB3RFWHRTb3VyY2UA9f+D6wAAAAh0RVh0Q29tbWVudAD2zJa/AAAABnRFWHRUaXRsZQCo7tInAAABAElEQVR4nO2de1zUVf7/3+dzmwsMoCgDXgARBO/"}], 
"AuthToken":"XkWQRd65+H+iPtlOoAEYAR0jrzB1o3UV"} 

我已經使用

jsonstr = new JSONStringer().object().key("Text") 
          .value(msg).key("Files").array().object().key(
            "ContentType").value("image/png").key(
            "Content").value(enimg) 
          .endObject().endArray().key("AuthToken").value(token) 
          .endObject(); 

但服務器是給我的回報故障信息，不接受數據。

Answer 1

其實我做的是對thing..everything是OK .. 問題是與org.json包它不準確與Base64字符串

我切換到另一個庫，所有工作..

https://stackoverflow.com/questions/338586/a-better-java-json-library

看到上面的問題，另一個JSON庫

，這是與org.json問題

我切換到another..and所有它的工作原理

nesting too deep in JSON... should I switch to XML?

Answer 2

可以使用的JSONObject類用於此目的 http://developer.android.com/reference/org/json/JSONObject.html

Answer 3

這是一種方式做你想要什麼：

// Creating root JSONObject 
JSONObject json = new JSONObject(); 

// Put in it a String field 
json.put("Text", "Hello sample"); 

// Creating a JSONArray 
JSONArray arr = new JSONArray(); 

//Creating the element to populate the array 
JSONObject element = new JSONObject(); 
element.put("ContentType","image/png"); 
element.put("Content","iVBORw0K...gDXgARBO/"); 
// Put it in the array 
arr.put(element); 

// Put the array and other fileds in the root JSONObject 
json.put("Files", arr); 
json.put("AuthToken", "XkWQ...o3UV"); 

// Get the JSON String 
String s = json.toString(); 
// Get formatted and indented JSON String 
String s2 = json.toString(4); 
// 4 is the number of spaces to indent the string