PHP郵件不包括身體

Question

我有這種形式

<form method="POST" action="mailer.php"> 
    <div id="email"><input type="email" name="email" class="email" placeholder="example@example.com"></div> 
</form> 

而這個PHP

<?php 

$email = $_POST['email']; 
$to = "test@test.com"; 
$subject = "ADD THIS EMAIL ADDRESS TO THE MAILING LIST"; 
$body = "\n\n"; 
$url = 'http://10.0.1.1/~ewiuf'; 
if (!filter_var($email, FILTER_VALIDATE_EMAIL)) { 
    echo '<script> alert("PLEASE ENTER A VALID EMAIL ADDRESS") </script>'; 
    echo '<META HTTP-EQUIV=Refresh CONTENT="0; URL=' . $url . '">'; 
} else { 
    if (mail($to, $subject, $body)) { 
     echo '<script> alert("THANK YOU FOR SUBSCRIBING TO THE NEWSLETTER") </script>'; 
     echo '<META HTTP-EQUIV=Refresh CONTENT="0; URL=' . $url . '">'; 
    } else { 
     echo '<script> alert("THERE WAS AN UNEXPECTED ERROR. PLEASE TRY AGAIN LATER") </script>'; 
     echo '<META HTTP-EQUIV=Refresh CONTENT="0; URL=' . $url . '">'; 
    } 
} 
?> 

爲什麼形式，這應該是電子郵件地址的內容，而不是被包括在主體腳本發送的電子郵件？該腳本發送，驗證，但用戶輸入表單的電子郵件地址不會發送給我。請幫助，謝謝。

Answer 1

你需要告訴它發送給你的用戶的電子郵件。 試試這個：

<?php 
$email = $_POST['email']; 
$to = "test@test.com"; 
$subject = "ADD THIS EMAIL ADDRESS TO THE MAILING LIST"; 
$body = "User Email: ".$email; 
$url = 'http://10.0.1.1/~ewiuf'; 
if(!filter_var($email, FILTER_VALIDATE_EMAIL)) 
{ 
echo '<script> alert("PLEASE ENTER A VALID EMAIL ADDRESS") </script>'; 
echo '<META HTTP-EQUIV=Refresh CONTENT="0; URL='.$url.'">'; 
} 
else 
{ 
if (mail($to, $subject, $body)) { 
echo '<script> alert("THANK YOU FOR SUBSCRIBING TO THE NEWSLETTER") </script>'; 
echo '<META HTTP-EQUIV=Refresh CONTENT="0; URL='.$url.'">'; 
} else { 
echo '<script> alert("THERE WAS AN UNEXPECTED ERROR. PLEASE TRY AGAIN LATER") </script>'; 
echo '<META HTTP-EQUIV=Refresh CONTENT="0; URL='.$url.'">'; 
} 
} 
?> 

Answer 2

$body = "\n\n";是你設置的唯一的地方或更改$body變量，這是你送的身體（第三個參數）的變量的mail功能。

在你的情況，我想你只想把電子郵件地址在身，所以你應該使用$body = $email;爲，或者只是使用$email代替$body作爲第三個參數來mail。

Answer 3

您正在$ body中發送「\ n \ n」。 如果我得到你的問題吧，你可能要$電子郵件地址添加到它，就像 $身體=「\ n \ n」 + $電子郵件

希望幫助