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我正在Android中編寫簡單的過濾器,並希望使用ExpandableListAdapter
複選框。ExpandableListView和複選框
我沒有創建列表或檢查複選框的問題。但我真的不知道如何記住選擇。關閉組並重新打開後,或者當我嘗試打開不同的組時,複選框會發生更改。
我試圖在網上閱讀,但我沒有找到如何解決我的問題。
這裏是我的代碼:
public class TasksFilterDialog extends Dialog{
private static final String TAG = "Filter Dialog";
private static final String ChildID = "ChildID";
private static final String GroupID = "GroupID";
private boolean[] statusCheck;
ExpandableListView list;
SimpleExpandableListAdapter listAdapter;
public TasksFilterDialog(Context context) {
super(context);
statusCheck = new boolean[Tasks.Status.values().length];
for(int i=0; i<statusCheck.length; i++)
statusCheck[i]=true;
}
@Override
protected void onCreate(Bundle savedInstanceState) {
Log.d(TAG, "Creating dialog");
this.setContentView(R.layout.tasks_filter);
list = (ExpandableListView)findViewById(R.id.filter_list);
setListAdapter(); // Setting Adapter Values to use on list
list.setAdapter(listAdapter); // Setting creating adapter to list
setOnChildClickListeners();
Log.d(TAG, "Creating dialog successfull");
}
private void setListAdapter() {
Log.d(TAG, "Setting list adapter");
listAdapter = new SimpleExpandableListAdapter(this.getContext(),
getGroups(),
R.layout.tasks_filter_groups_layout,
new String[] {GroupID},
new int[] {R.id.filter_group_text},
getChilds(),
R.layout.tasks_filter_simple_element,
new String[] {ChildID},
new int[] {R.id.filter_simple_element_text});
Log.d(TAG, "Setting list adapter successfull");
}
private List<HashMap<String, String>> getGroups() {
Log.d(TAG, "Adding groups values");
List<HashMap<String, String>> list = new ArrayList<HashMap<String, String>>();
HashMap<String, String> statusMap = new HashMap<String, String>();
statusMap.put(GroupID, "Status");
list.add(statusMap);
HashMap<String, String> usersMap = new HashMap<String, String>();
usersMap.put(GroupID, "Users");
list.add(usersMap);
Log.d(TAG, "Adding groups values successfull");
return list;
}
private List<List<HashMap<String, String>>> getChilds() {
Log.d(TAG, "Adding childs values");
List<List<HashMap<String, String>>> list = new ArrayList<List<HashMap<String, String>>>();
List<HashMap<String, String>> secList = new ArrayList<HashMap<String, String>>();
HashMap<String, String> map;
Tasks.Status status[] = Tasks.Status.values();
for(int i=0; i<status.length; i++) {
Log.d(TAG, "Adding child" + status[i].toString());
map = new HashMap<String, String>();
map.put(ChildID, status[i].toString());
secList.add(map);
}
list.add(secList);
list.add(secList);
Log.d(TAG, "Adding childs values succesfull");
return list;
}
private void setOnChildClickListeners() {
list.setOnChildClickListener(new OnChildClickListener() {
@Override
public boolean onChildClick(ExpandableListView list, View v,
int group, int id, long arg4) {
CheckBox cb = (CheckBox) v.findViewById(R.id.filter_simple_element_check);
cb.toggle();
switch(group){
case 0:
if(statusCheck[id])
statusCheck[id]=false;
else
statusCheck[id]=true;
break;
case 1:
//TODO After getting Tasks function
}
return false;
}
});
}
}
此行的用途:Tasks.Status status [] = Tasks.Status.values(); 。請給我解決方案 – 2012-08-16 06:49:50
我有我的expandablelistview中的複選框類似的問題。我已經想出了一種保存值的方法,但複選框變得複雜,使我無法從項目中的expandablelistview向前移動。請發佈代碼或回覆聯繫方式,因爲我非常有興趣瞭解您如何使用解決方案。 – AlleyOOP 2015-07-13 19:44:44