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我想我的SQL數據導出爲CSV文件但是當我這樣做,在CSV不會打印出的第一個條目只有第二個導出SQL爲CSV並打印出所有的條目
這裏是代碼:
<?php
$connect = mysqli_connect('localhost','root','','grad_gown');
if (!$connect){
die("Can not connect:". mysqli_error());
}
$db = new mysqli('localhost','root','','grad_gown');
//////////////////////////////////////
////////////////////////////////////////
if (isset($_POST['back'])){
header("Location: http://localhost/login_grad_2.php");
exit;
}
//////////////////////////////////////
//Exporting mysql database to excel file
$filename = 'uploads/'.strtotime("now").'.csv';
$fp = fopen($filename,"w");
$sql = $db -> query("SELECT * FROM `excel_info`") or die;
$row_234 = $sql -> fetch_assoc();
$seperator = "";
$comma = "";
//names/headers
foreach($row_234 as $name => $value){
$seperator .= $comma.''.str_replace('','""',$name);
$comma = ",";
}
$seperator .= "\n";
fputs($fp,$seperator);
///values display
while($row_234 = $sql -> fetch_assoc()){
$seperator = "";
$comma = "";
foreach($row_234 as $name => $value){
$seperator .= $comma.''.str_replace('','""',$value);
$comma = ",";
}
$seperator .= "\n";
fputs($fp,$seperator);
}
fclose($fp);
?>
那麼我的代碼有問題嗎?無論如何,我可以讓程序將我的所有條目從我的SQL顯示到CSV文件
您使用的是你取來呈現標題行第一行;但需要顯示它包含的數據 –
但爲什麼你忽略了PHP內置的[fputcsv()](http://www.php.net/manual/en/function.fputcsv.php)函數? –