PHP每個或每個打印數據

Question

首先感謝您的關注！

運行查詢後，我有這樣的結果：

-------------------------------------- 
|post_id| meta_key | meta_value | 
-------------------------------------- 
| 1 |  name  | jeff  | 
-------------------------------------- 
| 1 |  email | x@mail.com | 
-------------------------------------- 
| 1 |  color |  blue | 
-------------------------------------- 
| 2 |  name  | mary  | 
-------------------------------------- 
| 2 |  email | y@mail.com | 
-------------------------------------- 
| 2 |  color |  pink | 
-------------------------------------- 

的陣列

array(6) 
{ 
    [0]=> object(stdClass)#448 (3) 
     { 
      ["post_id"]  => string(1) "1" 
      ["meta_key"] => string(4) "name" 
      ["meta_value"] => string(4) "jeff" 
     } 
    [1]=> object(stdClass)#449 (3) 
     { 
      ["post_id"]  => string(1) "1" 
      ["meta_key"] => string(4) "email" 
      ["meta_value"] => string(10) "x@mail.com" 
     } 
    [2]=> object(stdClass)#450 (3) 
     { 
      ["post_id"]  => string(1) "1" 
      ["meta_key"] => string(5) "color" 
      ["meta_value"] => string(4) "blue" 
     } 
    [3]=> object(stdClass)#448 (3) 
     { 
      ["post_id"]  => string(1) "2" 
      ["meta_key"] => string(4) "name" 
      ["meta_value"] => string(4) "mary" 
     } 
    [4]=> object(stdClass)#449 (3) 
     { 
      ["post_id"]  => string(1) "2" 
      ["meta_key"] => string(4) "email" 
      ["meta_value"] => string(10) "y@mail.com" 
     } 
    [5]=> object(stdClass)#450 (3) 
     { 
      ["post_id"]  => string(1) "2" 
      ["meta_key"] => string(5) "color" 
      ["meta_value"] => string(4) "pink" 
     } 

}

好，我有3個標籤和3個值1組的ID。使用PHP，我需要知道如何做一個foreach或每個打印這個數據是這樣的：現在

--------------------------------------------------- 
|post_id| name  | email | color | 
--------------------------------------------------- 
| 1 | jeff  | x@mail.com | blue  | 
--------------------------------------------------- 
| 2 | mary  | y@mail.com | pink  | 
--------------------------------------------------- 

，與科斯塔斯Mitsarakis的幫助下，我有一個代碼，但是這個代碼，於我而言，是返回NULL值。

代碼：

global $wpdb; 

$meta_value = interested_get_meta('interested_email'); 
$results = $wpdb->get_results( 
     'SELECT post_id, meta_key, meta_value 
     FROM wp_postmeta 
     WHERE post_id 
     IN ( SELECT post_id 
       FROM wp_postmeta 
       WHERE meta_value = "'.$meta_value.'" 
      )', OBJECT 
); 

$data = array(); 
$result = array($results); 

foreach($result as $key => $value) { 
    if (!in_array($value['post_id'], $data)) { 
     $data[$value['post_id']]['post_id'] = $value['post_id']; 
    } 
    if ($value['meta_key'] != 'post_id') { 
     $data[$value['post_id']][$value['meta_key']] =  $value['meta_value']; 
    } 
} 

var_dump($data); 

的var_dump的回報：

array(1) { [""]=> array(2) { ["post_id"]=> NULL [""]=> NULL } } 

Answer 1

我在上面說的意見@KostasMitsarakis同意這可能是更好的SQL級別上完成的。

不過這裏是你可能尋找的PHP代碼：

<?php 

$input = [ 
    [ 
     'id' => 1, 
     'name' => 'jeff', 
     'email' => 'x@mail.com', 
     'color' => 'blue', 
    ], 
    [ 
     'id' => 2, 
     'name' => 'mary', 
     'email' => 'y@mail.c', 
     'color' => 'pink', 
    ] 
]; 

$output = []; 
foreach ($input as $entry) { 
    $element = []; 
    foreach($entry as $key=>$val) { 
     $element[$key] = $val; 
    } 
    $output[] = $element; 
} 


var_dump($output); 

這樣做的輸出繼電器是：

array(2) { 
    [0] => 
    array(4) { 
    'id' => 
    int(1) 
    'name' => 
    string(4) "jeff" 
    'email' => 
    string(10) "x@mail.com" 
    'color' => 
    string(4) "blue" 
    } 
    [1] => 
    array(4) { 
    'id' => 
    int(2) 
    'name' => 
    string(4) "mary" 
    'email' => 
    string(8) "y@mail.c" 
    'color' => 
    string(4) "pink" 
    } 
} 

Answer 2

你可以用一個簡單的foreach改變你的陣列：

$output = array(); 
foreach ($input as $data) { 
    $output[$data['id']]['id'] = $data['id']; 
    $output[$data['id']][$data['label']] = $data['value']; 
} 

Answer 3

嘗試使用ARRAY_A作爲數組獲得結果。

$meta_value = interested_get_meta('interested_email'); 
$results = $wpdb->get_results( 
     'SELECT post_id, meta_key, meta_value 
     FROM wp_postmeta 
     WHERE post_id 
     IN ( SELECT post_id 
       FROM wp_postmeta 
       WHERE meta_value = "'.$meta_value.'" 
      )', ARRAY_A 
); 

$data = array(); 
$result = json_decode($results , true); //Return results as array 

foreach($result as $key => $value) { 
    if (!in_array($value['post_id'], $data)) { 
     $data[$value['post_id']]['post_id'] = $value['post_id']; 
    } 
    if ($value['meta_key'] != 'post_id') { 
     $data[$value['post_id']][$value['meta_key']] = $value['meta_value']; 
    } 
} 
echo 'id name email color <br />'; 
foreach($data as $key => $value) { 
    echo $value['post_id'].' '.$value['name'].' '.$value['email'].' '.$value['color'].'<br />'; 
} 

var_dump($data); 

結果（表）

id name email color 
1 jeff x@mail.com blue 
2 mary y@mail.com pink 

結果（的var_dump）

array (size=2) 
    1 => 
    array (size=4) 
     'post_id' => int 1 
     'name' => string 'jeff' (length=4) 
     'email' => string 'x@mail.com' (length=10) 
     'color' => string 'blue' (length=4) 
    2 => 
    array (size=4) 
     'post_id' => int 2 
     'name' => string 'mary' (length=4) 
     'email' => string 'y@mail.com' (length=10) 
     'color' => string 'pink' (length=4) 

Answer 4

好，幾個小時和咖啡後，與所有的人的幫助，已經寫了在這裏，我找到了解決方案。

$meta_value = interested_get_meta('interested_email'); 

    global $wpdb; 
    $results = $wpdb->get_results( 
      'SELECT post_id, meta_key, meta_value 
      FROM wp_postmeta 
      WHERE post_id 
      IN ( SELECT post_id 
        FROM wp_postmeta 
        WHERE meta_value = "'.$meta_value.'" 
       )', OBJECT 
    ); 

    $data = array(); 

    if (is_array($results)) { 
     foreach($results as $item) { 
      $data[$item->post_id]['post_id']   = $item->post_id; 
      $data[$item->post_id][$item->meta_key] = $item->meta_value; 
     } 
    } 

    foreach ($data as $key => $value) { ?> 
     <li> 
      <?php echo $value['post_id'];?><br/> 
      <?php echo $value['name'];?><br/> 
      <?php echo $value['color'];?><br/> 
     </li> 
    <?php } 

感謝大家誰以任何方式幫助！