我有以下的PHP服務器代碼:PHP SOAP服務器返回的XML用沒有標籤
$xml ="<?xml version=\"1.0\" encoding=\"UTF-8\"?>";
$root = "Data";
$warmdata = "WarmData";
$brinedata = "BrineData";
$permindata = "PerMinData";
$xml .= "<$root>";
$xml .= "<$warmdata>";
foreach($result as $row)
{
$xml .= "<WarmIn>";
$xml .= $row['value'] . " " . $row['time'];
$xml .= "</WarmIn>";
}
foreach($result2 as $row)
{
$xml .= "<WarmOut>";
$xml .= $row['value'] . " " . $row['time'];
$xml .= "</WarmOut>";
}
$xml .= "</$warmdata>";
$xml .= "<$brinedata>";
foreach($result3 as $row)
{
$xml .= "<BrineIn>";
$xml .= $row['value'] . " " . $row['time'];
$xml .= "</BrineIn>";
}
foreach($result4 as $row)
{
$xml .= "<BrineOut>";
$xml .= $row['value'] . " " . $row['time'];
$xml .= "</BrineOut>";
}
$xml .= "</$brinedata>";
$xml .= "<$permindata>";
foreach($result5 as $row)
{
$xml .= "<WarmPerMin>";
$xml .= $row['value'] . " " . $row['time'];
$xml .= "</WarmPerMin>";
}
foreach($result6 as $row)
{
$xml .= "<BrinePerMin>";
$xml .= $row['value'] . " " . $row['time'];
$xml .= "</BrinePerMin>";
}
$xml .= "</$permindata>";
$xml .= "</$root>";
header ("Content-Type:text/xml");
return $xml;
$options=array('uri'=>'http://localhost/');
$server = new SoapServer(NULL,$options);
$server->setClass('DBData');
$server->handle();
我試圖讓使用SOAP客戶端正確格式化XML輸出,但是當我請求的XML,該出只包含從單個數據庫中檢索的數字,沒有實際的xml標記。 我該如何修改它,以便在輸出中使用標籤?
這是功能?如果沒有返回將終止執行 – RiggsFolly
@RiggsFolly是的,它是一個函數。它的工作原理,只有輸出缺少所有xml標籤,而是顯示在一行中。 – kisbovan93
那麼請顯示所有相關的代碼。我們只能調試我們所看到的**,我們不是千里眼的** – RiggsFolly