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爲什麼我必須調用新的Chart()來從同一個類(每個說法)中引發一個方法?這是做到這一點的正確方法嗎?謝謝。Javascript:使用原型時對象沒有方法
function Chart(location, startDateString, endDateString) {
this.location = location;
this.startDateString = startDateString;
this.endDateString = endDateString;
}
Chart.prototype.fnDrawStaticChart = function(chartUrl, chartData) {
$.get(chartUrl, function() {
$('#'+chartData.wrapSpecId).attr('src', chartUrl);
});
}
Chart.prototype.fnDraw = function(fnStaticChartJSON, fnStaticChartImage) {
$.getJSON(fnStaticChartJSON, function(data) {
if (data.chartData.length > 0) {
$('#chartDiv').append($('#template').jqote(data, '@'));
$.each(data.chartData, function(index, chartData) {
var pkgLineId = chartData.wrapSpec2.pkgLineId.pkgLineId;
var wrapSpecId = chartData.wrapSpecId;
var startDate = data.startDate;
var endDate = data.endDate;
var chartUrl = fnStaticChartImage({
pkg_line_id: pkgLineId,
wrap_spec_id: wrapSpecId,
start_date: startDate,
end_date: endDate
});
this.fnDrawStaticChart(chartUrl, chartData); //can't do this.
new Chart().fnDrawStaticChart(chartUrl, chartData); CAN do this.
});
});
}
好的很酷。那麼爲什麼我不能像this.fnDrawStaticChart()那樣調用它呢? 「this」引用$ .getJSON中的某些內容嗎? –
不,* this *總是指您正在使用的函數的當前範圍,在您的情況下是您傳遞給$ .each()的函數(index,chartData)。 – Daff