將顏色RGB轉換爲HEX（int結果）

我已經創建了一個將三個整數值轉換爲十六進制值（字符串）的方法，如下所示（PS：尚未測試過）：將顏色RGB轉換爲HEX（int結果）

protected String convertRGBToHex(int r, int g, int b) { 

    String rFString, rSString, gFString, gSString, bFString, bSString, result; 
    int red, green, blue; 
    int rred, rgreen, rblue; 

    red = r/16; 
    rred = r % 16; 

    if (red == 10) rFString = "A"; 
    else if (red == 11) rFString = "B"; 
    else if (red == 12) rFString = "C"; 
    else if (red == 13) rFString = "D"; 
    else if (red == 14) rFString = "E"; 
    else if (red == 15) rFString = "F"; 
    else rFString = String.valueOf(red); 

    if (rred == 10) rSString = "A"; 
    else if (rred == 11) rSString = "B"; 
    else if (rred == 12) rSString = "C"; 
    else if (rred == 13) rSString = "D"; 
    else if (rred == 14) rSString = "E"; 
    else if (rred == 15) rSString = "F"; 
    else rSString = String.valueOf(rred); 

    rFString = rFString + rSString; 

    green = g/16; 
    rgreen = g % 16; 

    if (green == 10) gFString = "A"; 
    else if (green == 11) gFString = "B"; 
    else if (green == 12) gFString = "C"; 
    else if (green == 13) gFString = "D"; 
    else if (green == 14) gFString = "E"; 
    else if (green == 15) gFString = "F"; 
    else gFString = String.valueOf(green); 

    if (rgreen == 10) gSString = "A"; 
    else if (rgreen == 11) gSString = "B"; 
    else if (rgreen == 12) gSString = "C"; 
    else if (rgreen == 13) gSString = "D"; 
    else if (rgreen == 14) gSString = "E"; 
    else if (rgreen == 15) gSString = "F"; 
    else gSString = String.valueOf(rgreen); 

    gFString = gFString + gSString; 

    blue = b/16; 
    rblue = b % 16; 

    if (blue == 10) bFString = "A"; 
    else if (blue == 11) bFString = "B"; 
    else if (blue == 12) bFString = "C"; 
    else if (blue == 13) bFString = "D"; 
    else if (blue == 14) bFString = "E"; 
    else if (blue == 15) bFString = "F"; 
    else bFString = String.valueOf(blue); 

    if (rblue == 10) bSString = "A"; 
    else if (rblue == 11) bSString = "B"; 
    else if (rblue == 12) bSString = "C"; 
    else if (rblue == 13) bSString = "D"; 
    else if (rblue == 14) bSString = "E"; 
    else if (rblue == 15) bSString = "F"; 
    else bSString = String.valueOf(rblue); 

    bFString = bFString + bSString; 

    result = "#" + rFString + gFString + bFString; 

    return result; 

}

我的問題是：有，我可以在這個字符串結果轉換爲int值，我可以用這樣的方式的方式：

view.setBackgroundColor(0xF82619);

或者是療法的方式爲int的字符串轉換和比它（沒有崩潰）：

view.setBackgroundColor(result);

謝謝！

來源

2013-08-20 Dehumanizer

你爲什麼不直接轉換成int值以十六進制 – karan421

不要寫是一個int轉換爲十六進制字符串值的方法。這是一項基本任務，語言（或基礎API）將始終提供執行該任務的方法（或函數）。在java中，String.format（）是方法;試試這個：String output = String.format（「＃％02x％02x％02x」，10,11,56）; – DwB

假設你的字符串是

String col = "0xF82619";

嘗試：

view.setBackgroundColor(Color.parseColor(col));

來源

2013-08-20 17:53:43

有一個更簡單的方法.... – VoronoiPotato

將其轉換爲第一個字符串，然後直接十六進制轉換它由

Integer.valueOf(String.valueOf(n), 16);

它會爲十六進制，而不是提高你的代碼的性能。

來源

2013-08-20 17:55:29 karan421

爲了得到一個整數，你可以做

int col = (0xff << 24) | ((r&0xff) << 16) | ((g&0xff) << 8) | (b&0xff);

更爲容易的是：

int col = Color.rgb(r, g, b);

來源

2013-08-20 17:56:13 Henry

亨利，它不工作： int r = 255，g = 40，b = 100; int col =（（r＆0xff）<< 16）| （（g＆0xff）<< 8）| （b &0xff); view.setBackgroundColor（col）; – Dehumanizer

是的，我忘記了alpha通道，一個不透明的顏色有alpha255。查看更新後的答案。 – Henry

將顏色RGB轉換爲HEX（int結果）

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