爲什麼下面的php代碼不工作？

Question

錯誤說解析錯誤：語法錯誤，意想不到的T_STRING，上線11 期待T_VARIABLE我已經使用相同的代碼之前也和它在那裏工作精細

class connection{ 

// variables for cms login 

var $admin_name1 = "name"; 
var $admin_passwd1 = "passwd"; 
// variable to recieve data from form 

var rename; //********** this line is giving error 
var repasswd; 

function cms_login() 
{ 
if(($this->rename == $this->admin_name1) && ($this->repasswd == $this->admin_passwd1)){ // access granted 
echo 'Access granted<br>'; 
echo 'Please wait while you are being redirected'; 
session_start(); 
$_SESSION['piratica']="active"; 
$redirect = "Location: landing.php"; 
echo header($redirect); 
} 
else { // access denied 
echo 'WARNING !!'; 
echo '<br>Wrong login details.'; 

} 

} // function cms_login ends here 


} // class connection ends here 

Answer 1

你忘了$跡象變量前面名。

var $rename; //********** this line is giving error 
var $repasswd; 

Answer 2

在PHP中的所有變量開始$

你忘了添加了重命名和repasswd變量