爲什麼我的MySQL結果意外重複？

我有3個數據庫表。 1有細節，1有功能，1有小時。該功能和小時表具有來自詳細信息表的ID和ID。我想要做的是創建1個數組，其中有3個數組，其中一個用於細節，1個用於特徵，1個用於小時。這裏是我的代碼：爲什麼我的MySQL結果意外重複？

$query = mysqli_query($connection, " 
SELECT `modelHomes`.`id`, 'testname' as `name`, `modelHomes`.`sqft`, 
    '123 Fake St' as `address`, '555-5555' as `phone`, `modelHomes`.`galleryid`, 
    `modelHomes`.`virtualtourid`, `modelHomeFeatures`.`text` as `feature`, 
    `modelHomeHours`.`text` as `hour` 
FROM `modelHomes` 
INNER JOIN `modelHomeFeatures` ON `modelHomeFeatures`.`modelhomeid` = `modelHomes`.`id` 
INNER JOIN `modelHomeHours` ON `modelHomeHours`.`modelhomeid` = `modelHomes`.`id` 
"); 

       $results = array(); 
       while($row = mysqli_fetch_assoc($query)){ 

         $results[] = $row; 

       } 
       return $results;

它返回：

Array ([0] => Array ([id] => 1 [name] => testname [sqft] => 2501 [address] => 123 Fake St [phone] => 555-5555 [galleryid] => 9 [virtualtourid] => 1 [feature] => 4 Bedrooms [hour] => Mon-Thurs 1pm-6pm) [1] => Array ([id] => 1 [name] => testname [sqft] => 2501 [address] => 123 Fake St [phone] => 555-5555 [galleryid] => 9 [virtualtourid] => 1 [feature] => 4 Bedrooms [hour] => Friday 12pm-5pm) [2] => Array ([id] => 1 [name] => testname [sqft] => 2501 [address] => 123 Fake St [phone] => 555-5555 [galleryid] => 9 [virtualtourid] => 1 [feature] => 4 Bedrooms [hour] => Sat-Sun 12pm-5pm) [3] => Array ([id] => 1 [name] => testname [sqft] => 2501 [address] => 123 Fake St [phone] => 555-5555 [galleryid] => 9 [virtualtourid] => 1 [feature] => 2 Sided Gas Fireplace [hour] => Mon-Thurs 1pm-6pm) [4] => Array ([id] => 1 [name] => testname [sqft] => 2501 [address] => 123 Fake St [phone] => 555-5555 [galleryid] => 9 [virtualtourid] => 1 [feature] => 2 Sided Gas Fireplace [hour] => Friday 12pm-5pm) [5] => Array ([id] => 1 [name] => testname [sqft] => 2501 [address] => 123 Fake St [phone] => 555-5555 [galleryid] => 9 [virtualtourid] => 1 [feature] => 2 Sided Gas Fireplace [hour] => Sat-Sun 12pm-5pm) [6] => Array ([id] => 1 [name] => testname [sqft] => 2501 [address] => 123 Fake St [phone] => 555-5555 [galleryid] => 9 [virtualtourid] => 1 [feature] => All Oak Staircase with Open Risers [hour] => Mon-Thurs 1pm-6pm) [7] => Array ([id] => 1 [name] => testname [sqft] => 2501 [address] => 123 Fake St [phone] => 555-5555 [galleryid] => 9 [virtualtourid] => 1 [feature] => All Oak Staircase with Open Risers [hour] => Friday 12pm-5pm) [8] => Array ([id] => 1 [name] => testname [sqft] => 2501 [address] => 123 Fake St [phone] => 555-5555 [galleryid] => 9 [virtualtourid] => 1 [feature] => All Oak Staircase with Open Risers [hour] => Sat-Sun 12pm-5pm) [9] => Array ([id] => 1 [name] => testname [sqft] => 2501 [address] => 123 Fake St [phone] => 555-5555 [galleryid] => 9 [virtualtourid] => 1 [feature] => Upgraded Hardwood Flooring & Berber Carpet [hour] => Mon-Thurs 1pm-6pm) [10] => Array ([id] => 1 [name] => testname [sqft] => 2501 [address] => 123 Fake St [phone] => 555-5555 [galleryid] => 9 [virtualtourid] => 1 [feature] => Upgraded Hardwood Flooring & Berber Carpet [hour] => Friday 12pm-5pm) [11] => Array ([id] => 1 [name] => testname [sqft] => 2501 [address] => 123 Fake St [phone] => 555-5555 [galleryid] => 9 [virtualtourid] => 1 [feature] => Upgraded Hardwood Flooring & Berber Carpet [hour] => Sat-Sun 12pm-5pm) [12] => Array ([id] => 1 [name] => testname [sqft] => 2501 [address] => 123 Fake St [phone] => 555-5555 [galleryid] => 9 [virtualtourid] => 1 [feature] => Upgraded Ceramic Backsplash [hour] => Mon-Thurs 1pm-6pm) [13] => Array ([id] => 1 [name] => testname [sqft] => 2501 [address] => 123 Fake St [phone] => 555-5555 [galleryid] => 9 [virtualtourid] => 1 [feature] => Upgraded Ceramic Backsplash [hour] => Friday 12pm-5pm) [14] => Array ([id] => 1 [name] => testname [sqft] => 2501 [address] => 123 Fake St [phone] => 555-5555 [galleryid] => 9 [virtualtourid] => 1 [feature] => Upgraded Ceramic Backsplash [hour] => Sat-Sun 12pm-5pm) [15] => Array ([id] => 1 [name] => testname [sqft] => 2501 [address] => 123 Fake St [phone] => 555-5555 [galleryid] => 9 [virtualtourid] => 1 [feature] => 9' Main Floor Ceilings [hour] => Mon-Thurs 1pm-6pm) [16] => Array ([id] => 1 [name] => testname [sqft] => 2501 [address] => 123 Fake St [phone] => 555-5555 [galleryid] => 9 [virtualtourid] => 1 [feature] => 9' Main Floor Ceilings [hour] => Friday 12pm-5pm) [17] => Array ([id] => 1 [name] => testname [sqft] => 2501 [address] => 123 Fake St [phone] => 555-5555 [galleryid] => 9 [virtualtourid] => 1 [feature] => 9' Main Floor Ceilings [hour] => Sat-Sun 12pm-5pm) [18] => Array ([id] => 1 [name] => testname [sqft] => 2501 [address] => 123 Fake St [phone] => 555-5555 [galleryid] => 9 [virtualtourid] => 1 [feature] => Fruit Cellar Under Porch [hour] => Mon-Thurs 1pm-6pm) [19] => Array ([id] => 1 [name] => testname [sqft] => 2501 [address] => 123 Fake St [phone] => 555-5555 [galleryid] => 9 [virtualtourid] => 1 [feature] => Fruit Cellar Under Porch [hour] => Friday 12pm-5pm) [20] => Array ([id] => 1 [name] => testname [sqft] => 2501 [address] => 123 Fake St [phone] => 555-5555 [galleryid] => 9 [virtualtourid] => 1 [feature] => Fruit Cellar Under Porch [hour] => Sat-Sun 12pm-5pm) [21] => Array ([id] => 1 [name] => testname [sqft] => 2501 [address] => 123 Fake St [phone] => 555-5555 [galleryid] => 9 [virtualtourid] => 1 [feature] => Upgraded Wrap Around Porch [hour] => Mon-Thurs 1pm-6pm) [22] => Array ([id] => 1 [name] => testname [sqft] => 2501 [address] => 123 Fake St [phone] => 555-5555 [galleryid] => 9 [virtualtourid] => 1 [feature] => Upgraded Wrap Around Porch [hour] => Friday 12pm-5pm) [23] => Array ([id] => 1 [name] => testname [sqft] => 2501 [address] => 123 Fake St [phone] => 555-5555 [galleryid] => 9 [virtualtourid] => 1 [feature] => Upgraded Wrap Around Porch [hour] => Sat-Sun 12pm-5pm))

我不知道爲什麼結果不斷重複。我試圖調整我的代碼像這樣：

$results['hours'][] = $row['hour']; 
$results['features'][] = $row['feature']; 
$results['details'][] = $row;

但我的結果不斷重複。這是我得到的輸出：

如何在1個數組內沒有數據重複的情況下將結果轉換爲3個數組？

這是當我進入查詢到phpMyAdmin的我得到的結果：

enter image description here

我所尋找的是1個陣列ID，姓名，平方英尺，地址，電話，galleryid和virtualtourid， 1個具有特徵（不重複）的陣列和1個具有小時（不重複）的陣列。

來源

2014-07-04 user3723240

結果重複，因爲你的查詢返回結果重複。這種代碼無法將數組推動到數組中，除非結果是從頭開始的。你是否手動運行該查詢並查看結果是什麼？ –

是的，我已經在phpMyAdmin運行此查詢，我的結果是我在圖片的形式問題。 – user3723240

如果你正確格式化您的數組轉儲，你會看到他們是** **不重複。'小時'值正在改變，就像它們在你的screencap中一樣。 –

我會用GROUP_CONCAT分組的時間：

選擇modelHomes。 id， '測試名' 爲name，modelHomes。 sqft， '123假聖' 爲address， '555-5555' 爲phone，modelHomes。 galleryid， modelHomes。 virtualtourid，modelHomeFeatures。 text如feature， GROUP_CONCAT（modelHomeHours。text）作爲hour FROM modelHomes INNER JOIN modelHomeFeatures ON modelHomeFeatures。 modelhomeid = modelHomes。 id INNER JOIN modelHomeHours ON modelHomeHours。 modelhomeid = modelHomes。 id GROUP BY modelHomes.id

試試這個

$query = mysqli_query($connection,"SELECT modelHomes.id, 'testname' as name, modelHomes.sqft,'123 Fake St' as address, '555-5555' as phone, modelHomes.galleryid,modelHomes.virtualtourid, 
             modelHomeFeatures.text as feature,GROUP_CONCAT(modelHomeHours.text) as hour 
            FROM modelHomes 
           INNER JOIN modelHomeFeatures ON modelHomeFeatures.modelhomeid = modelHomes.id 
           INNER JOIN modelHomeHours ON modelHomeHours.modelhomeid = modelHomes.id 
          GROUP BY modelHomes.id"); 
$results = array(); 
while($row = mysqli_fetch_assoc($query)){ 
    $ahours=explode(",",$row["hour"]); 
    array_push($results,array(id=>$row["id"], 
           name=>$row["name"], 
           sqft=>$row["sqft"], 
           address=>$row["address"], 
           phone=>$row["phone"], 
           galleryid=>$row["galleryid"], 
           virtualtourid=>$row["virtualtourid"], 
           feature=>$row["feature"], 
           hour=>$ahours)); 
} 
return $results;

ANOTHER的形式給出了查詢

SELECT modelHomes.id, 'testname' as name, modelHomes.sqft, 
      '123 Fake St' as address, '555-5555' as phone, 
      modelHomes.galleryid,modelHomes.virtualtourid, 
      (SELECT GROUP_CONCAT(modelHomeFeatures.text) 
       FROM modelHomeFeatures 
      WHERE modelHomeFeatures.modelhomeid = modelHomes.id) as feature, 
      (SELECT GROUP_CONCAT(modelHomeHours.text) 
       FROM modelHomeHours 
      WHERE modelHomeHours.modelhomeid = modelHomes.id) as hour 
     FROM modelHomes 
    GROUP BY modelHomes.id

來源

2014-07-04 15:42:23 bitsm

那不是我在找什麼...我不認爲我的問題是與我的查詢，我認爲它更多的在PHP方面，我怎麼用我的結果 – user3723240

我唯一的問題是，當我GROUP_CONCAST（modelHomeFeatures.text ）的功能重複 – user3723240

嘗試其他方法查詢 – bitsm

爲什麼我的MySQL結果意外重複？

回答

相關問題