無法使用密集等級獲得期望的輸出

Question

您能否請幫助我如何獲得預期的輸出，如下面的屏幕截圖所示？

DECLARE @TT TABLE (CUSTOMERID INT, TYPE VARCHAR(100) , D1 DATE) 
INSERT INTO @TT VALUES (15001,'TYPE1', '4/1/2017') 
INSERT INTO @TT VALUES (15001,'TYPE1', '4/2/2017') 
INSERT INTO @TT VALUES (15001,'TYPE1', '4/3/2017') 
INSERT INTO @TT VALUES (15001,'NON TYPE1', '4/4/2017') 
INSERT INTO @TT VALUES (15001,'NON TYPE1', '4/5/2017') 
INSERT INTO @TT VALUES (15001,'NON TYPE1', '4/6/2017') 
INSERT INTO @TT VALUES (245,'Non TYPE1', '4/1/2017') 
INSERT INTO @TT VALUES (245,'Non TYPE1', '4/2/2017') 
INSERT INTO @TT VALUES (245,'Non TYPE1', '4/3/2017') 
INSERT INTO @TT VALUES (245,'TYPE1', '4/4/2017') 
INSERT INTO @TT VALUES (245,'TYPE1', '4/5/2017') 
INSERT INTO @TT VALUES (245,'TYPE1', '4/6/2017') 

查詢是：

SELECT * , 
     DENSE_RANK() OVER (PARTITION BY CUSTOMERID ORDER BY CUSTOMERID,TYPE) DR 
FROM @TT 
WHERE CUSTOMERID = 15001 
ORDER BY CUSTOMERID,D1 

SELECT *, 
     DENSE_RANK() OVER (PARTITION BY CUSTOMERID ORDER BY CUSTOMERID,TYPE) DR 
FROM @TT 
WHERE CUSTOMERID = 245 
ORDER BY CUSTOMERID,D1 

謝謝你的幫助。

Answer 1

您想按最短日期排序。我認爲這是這樣的：

SELECT t.*, 
     DENSE_RANK() OVER (PARTITION BY CUSTOMERID ORDER BY mind1, TYPE) DR 
FROM (SELECT t.*, MIN(d1) OVER (PARTITION BY CUSTOMERID, TYPE) as mind1 
     FROM @TT t 
    ) t 
WHERE CUSTOMERID = 15001 
ORDER BY CUSTOMERID, D1; 

這種假定類型不交錯（如在你的例子）。如果是這種情況，那麼請提出另一個問題。這顯着改變了這個問題。這個問題也應該提供更好的樣本數據和期望的結果。