在Laravel中選擇，修改並插入結果作爲新記錄

Question

當我使用save（）方法或使用分開的調用如create或update時，如何強制laravel始終創建新記錄。例如，我想從表中獲取一些記錄，修改它們並將它們保存爲新記錄。

$products = Product::where('category_id', 10)->get(); 

foreach($products as $product){ 
    $product->name = 'new name'; 
    $product->save(); 
} 

上面的腳本，更新記錄，在phalconphp我可以是具體的，說$product->create()和新的記錄將創建。

Laravel可能嗎？

Answer 1

下面是克隆使用replicate模型更簡單的方法：

$products = Product::where('category_id', 10)->get(); 

foreach($products as $product) 
{ 
    // Clone the model 
    $clone = $product->replicate(); 

    // Apply any changes you want to the cloned model 
    $clone->name = 'new name'; 
    // ... 

    // Save the cloned/modified model as a different record 
    $clone->save(); 
} 

Answer 2

爲什麼不......

$products = Product::where('category_id', 10)->get(); 

foreach($products as $product){ 
    $new_product = new Product(); 
    $new_product->name = 'new name'; 
    $new_product->other_column = $product->other_column; 
    $new_product->save(); 
} 

Answer 3

也許你需要像下面這樣？創建一個新產品，並從現有產品中設置它的屬性或分配一個新值。

$products = Product::where('category_id', 10)->get(); 

foreach($products as $product){  

$newproduct = new Product; 
$newproduct ->name = $product->name; // or assign a new value 
$newproduct ->attribute1 = $product->attribute1; // or assign a new value 
$newproduct ->attribute2 = $product->attribute2;// or assign a new value 
$newproduct ->attribute3 = $product->attribute3;// or assign a new value 
$newproduct ->save(); 
}