根據「divider」字符將PHP字符串劃分爲排列的子字符串

Question

我想要做的是將一個PHP字符串分成一組子字符串，這些子字符串根據開始這些子字符串的「divider」字符分組爲數組。字符*,^和%被保留爲分隔符。所以，如果我有串"*Here's some text^that is meant*to be separated^based on where%the divider characters^are"，應該分裂並放置在陣列像這樣：

array(2) { 
    [0] => "*Here's some text" 
    [1] => "*to be separated" 
} 

array(3) { 
    [0] => "^that is meant" 
    [1] => "^based on where" 
    [2] => "^are" 
} 

array(1) { 
    [0] => "%the divider characters" 
} 

我完全失去了在這一個。有誰知道如何實現這一點？

Answer 1

，如果你想你不爲$matches[0]所以取消它問：

preg_match_all('/(\*[^\*\^%]+)|(\^[^\*\^%]+)|(%[^\*\^%]+)/', $string, $matches); 
$matches = array_map('array_filter', $matches); 

print_r($matches); 

的array_filter()去除捕獲組子陣列空瓶給在這個問題

Answer 2

另一個所示的陣列方法（優化）..

$matches = array(); 
preg_match_all('/[\*\^\%][^\*\^\%]+/', $str, $matches); 
var_dump($matches);