<?php
echo "Hello test <br>";
$userid = $_GET['userid'];
echo "your user userid is " . $userid . " &";
$salt = $_GET['salt'];
echo " your user salt is " . $salt;
// Query for finding the data from db
// Issue in query
$sql = "SELECT * FROM test.test where id=" .$userid AND "salt=".$salt;
echo "<br>" . $sql;
$result = $conn->query($sql);
if (!empty($result))
{
echo "<br>Result Found";
}
else
{
echo "<br> Invalid link !";
}
// }
?>
我的查詢無法正常工作。如果我減少我的查詢id=".$userid
它工作正常,但如果我添加其餘部分不工作。問題。不工作
至少使用的代碼高亮編輯器。這將避免你偶然發現像這樣的簡單語法錯誤。 –