zip4j在Java

荏苒文件和文件夾我希望在Java中創建一個zip程序，它zip文件和文件夾，讓說結構是這樣 -zip4j在Java

文件夾，一個/
文件夾，1個/ 1 .TXT
夾酮/ two.mp3
夾酮/ three.jpg
夾個/
夾個/ four.doc
文件夾個/ five.rtf
文件夾兩/文件夾三/
文件夾兩/文件夾三/ six.txt

我用zip4j開源的，我已經收集了所有在一個列表文件（絕對路徑），然後給它來壓縮，但它是文件壓縮和解僅在my.zip -

此時就把one.txt存盤
two.mp3
three.jpg
four.doc
five.rtf
six.txt

我怎麼能保持在壓縮和解壓，因爲它是當地較早相同的結構。請建議其他開放源代碼是否可以幫助我像使用其他Windows壓縮程序一樣壓縮/解壓縮相同的結構文件和文件夾。

代碼如下 -

public class CreateZipWithOutputStreams { 

    ArrayList filesToAdd = new ArrayList(); 

    public void CreateZipWithOutputStreams(String sAbsolutePath) { 


     ZipOutputStream outputStream = null; 
     InputStream inputStream = null; 

     try { 

      ArrayList arrLocal = exploredFolder(sAbsolutePath); 


      outputStream = new ZipOutputStream(new FileOutputStream(new File("c:\\ZipTest\\CreateZipFileWithOutputStreams.zip"))); 

      ZipParameters parameters = new ZipParameters(); 

      parameters.setCompressionMethod(Zip4jConstants.COMP_DEFLATE); 


      parameters.setCompressionLevel(Zip4jConstants.DEFLATE_LEVEL_NORMAL); 

      parameters.setEncryptFiles(true); 

      parameters.setEncryptionMethod(Zip4jConstants.ENC_METHOD_AES); 


      parameters.setAesKeyStrength(Zip4jConstants.AES_STRENGTH_256); 


      parameters.setPassword("neelam"); 


      for (int i = 0; i < arrLocal.size(); i++) { 
       File file = (File) arrLocal.get(i); 


       outputStream.putNextEntry(file, parameters); 

       if (file.isDirectory()) { 
        outputStream.closeEntry(); 
        continue; 
       } 


       inputStream = new FileInputStream(file); 
       byte[] readBuff = new byte[4096]; 
       int readLen = -1; 

       while ((readLen = inputStream.read(readBuff)) != -1) { 
        outputStream.write(readBuff, 0, readLen); 
       } 

       outputStream.closeEntry(); 

       inputStream.close(); 
      } 

      outputStream.finish(); 

     } catch (Exception e) { 
      e.printStackTrace(); 
     } finally { 
      if (outputStream != null) { 
       try { 
        outputStream.close(); 
       } catch (IOException e) { 
        e.printStackTrace(); 
       } 
      } 

      if (inputStream != null) { 
       try { 
        inputStream.close(); 
       } catch (IOException e) { 
        e.printStackTrace(); 
       } 
      } 
     } 
    } 

    public ArrayList exploredFolder(String sAbsolutePath) { 
     File[] sfiles; 
     File fsSelectedPath = new File(sAbsolutePath); 
     sfiles = fsSelectedPath.listFiles(); 
     if (sfiles == null) { 
      return null; 
     } 
     for (int j = 0; j < sfiles.length; j++) { 
      File f = sfiles[j]; 
      if (f.isDirectory() == true) { 
       exploredFolder(f.getAbsolutePath()); 
      } else { 
       filesToAdd.add(f); 

      } 
     } 
     return filesToAdd; 
    } 


    public static void main(String[] args) { 
     new CreateZipWithOutputStreams().CreateZipWithOutputStreams("c:\\ZipTest"); 
    } 
}

謝謝！

來源

2012-09-24 Neelam Sharma