我安裝了英特爾ComposerXE 2013的試用版(包含ICC 14.0.1編譯器)。我的測試程序如下:爲什麼一個額外的-I標誌(包含目錄)中斷編譯? (使用英特爾編譯器)
#include <boost/graph/adjacency_list.hpp>
#include <iostream>
typedef boost::adjacency_list<boost::vecS, boost::vecS, boost::undirectedS> UndirectedGraph;
int main() {
UndirectedGraph G(10);
return 0;
}
我使用英特爾編譯器標誌如下
/home/intel/bin/icpc //binary
-L/home/intel/composerxe/lib/intel64 //lib path
-I/home/intel/composerxe/include //include path for ICPC
-I/home/boost_1_55_0 //boost path
-std=c++11 test.cpp // c++11 flags
我得到下面的錯誤BOOST HASH.hpp
和type_traits.hpp
文件
In file included from /home/boost_1_55_0/boost/functional/hash/hash.hpp(540),
from /home/boost_1_55_0/boost/functional/hash.hpp(6),
from /home/boost_1_55_0/boost/unordered/unordered_set.hpp(20),
from /home/boost_1_55_0/boost/unordered_set.hpp(16),
from /home/boost_1_55_0/boost/graph/adjacency_list.hpp(21),
from test.cpp(1):
/home/boost_1_55_0/boost/functional/hash/extensions.hpp(67): error: "hash_value" is not a function or static data member
std::size_t hash_value(std::complex<T> const&);
^
In file included from /home/boost_1_55_0/boost/functional/hash/hash.hpp(540),
from /home/boost_1_55_0/boost/functional/hash.hpp(6),
from /home/boost_1_55_0/boost/unordered/unordered_set.hpp(20),
from /home/boost_1_55_0/boost/unordered_set.hpp(16),
from /home/boost_1_55_0/boost/graph/adjacency_list.hpp(21),
from test.cpp(1):
/home/boost_1_55_0/boost/functional/hash/extensions.hpp(121): error: "hash_value" is not a function or static data member
std::size_t hash_value(std::complex<T> const& v)
^
In file included from /home/boost_1_55_0/boost/functional/hash/hash.hpp(540),
from /home/boost_1_55_0/boost/functional/hash.hpp(6),
from /home/boost_1_55_0/boost/unordered/unordered_set.hpp(20),
from /home/boost_1_55_0/boost/unordered_set.hpp(16),
from /home/boost_1_55_0/boost/graph/adjacency_list.hpp(21),
from test.cpp(1):
/home/boost_1_55_0/boost/functional/hash/extensions.hpp(277): warning #12: parsing restarts here after previous syntax error
};
^
In file included from /home/boost_1_55_0/boost/type_traits.hpp(49),
from /home/boost_1_55_0/boost/pending/property.hpp(13),
from /home/boost_1_55_0/boost/graph/graph_traits.hpp(27),
from /home/boost_1_55_0/boost/graph/adjacency_list.hpp(33),
from test.cpp(1):
/home/boost_1_55_0/boost/type_traits/is_complex.hpp(23): error #303: explicit type is missing ("int" assumed)
is_convertible_from_tester(const std::complex<T>&);
^
In file included from /home/boost_1_55_0/boost/type_traits.hpp(49),
from /home/boost_1_55_0/boost/pending/property.hpp(13),
from /home/boost_1_55_0/boost/graph/graph_traits.hpp(27),
from /home/boost_1_55_0/boost/graph/adjacency_list.hpp(33),
from test.cpp(1):
/home/boost_1_55_0/boost/type_traits/is_complex.hpp(23): error: qualified name is not allowed
is_convertible_from_tester(const std::complex<T>&);
^
In file included from /home/boost_1_55_0/boost/type_traits.hpp(49),
from /home/boost_1_55_0/boost/pending/property.hpp(13),
from /home/boost_1_55_0/boost/graph/graph_traits.hpp(27),
from /home/boost_1_55_0/boost/graph/adjacency_list.hpp(33),
from test.cpp(1):
/home/boost_1_55_0/boost/type_traits/is_complex.hpp(23): error: expected a ")"
is_convertible_from_tester(const std::complex<T>&);
^
In file included from /home/boost_1_55_0/boost/type_traits.hpp(49),
from /home/boost_1_55_0/boost/pending/property.hpp(13),
from /home/boost_1_55_0/boost/graph/graph_traits.hpp(27),
from /home/boost_1_55_0/boost/graph/adjacency_list.hpp(33),
from test.cpp(1):
/home/boost_1_55_0/boost/type_traits/is_complex.hpp(22): warning #488: template parameter "T" is not used in declaring the parameter types of function template "boost::detail::is_convertible_from_tester::is_convertible_from_tester"
template <class T>
^
現在編譯的代碼我在沒有ICPC的情況下使用此編譯INCLUDE PATH
/home/intel/bin/icpc //binary
-L/home/intel/composerxe/lib/intel64 //lib path
//removed the ICPC INCLUDE PATH HERE
-I/home/boost_1_55_0 //boost path
-std=c++11 test.cpp // c++11 flags
這個編譯就好了ZERO錯誤
爲什麼會發生這種情況?
我的LD_LIBRARY_PATH
和PATH
變量爲空。沒有GCC或其路徑設置的其他編譯器。我正在編譯期間提供所有的路徑。
你會不會通過任何機會,有下安裝升壓版本'/家庭/英特爾/ composerxe/include'? – rodrigo