多XMLAGG

Question

我有一個問題，我需要創建一個具有類似格式的XML：

<Root> 
<Bank>--Can be repeated 
<ID> 
    <Credit>--Can be repeated 
      <INFO> --Can be repeated 
      </INFO> 
    <Credit> 
</ID> 
</Bank> 
</Root> 

所以這就像XMLAGG，到XMLAGG到XMLAGG

我有一個表，像這樣：

 
BANK| ID | CREDIT | INFO || 
1  A1  B1  C1 
1  A1  B1  C2 
1  A1  B1  C3 
1  A1  B2  D1 
1  A1  B2  D2 
1  A1  B1  C1 
2  X1  Y1  Z1 

我想有像XML：

<Root> 
<Bank> 1 </Bank> 
<ID> A1 </ID> 
    <CREDIT> B1 
      <INFO> C1 </INFO> 
      <INFO> C2 </INFO> 
      <INFO> C2 </INFO> 
    </CREDIT> 
    <CREDIT> B2 
      <INFO> D1 </INFO> 
      <INFO> D2 </INFO> 
    </CREDIT> 
</ID> 
<BANK> 2 </BANK> 
<ID> X1 </ID> 
<CREDIT> Y1</CREDIT> 
<INFO> Z1 </INFO> 
</Root> 

我希望你明白我的觀點，謝謝！

Answer 1

您的描述非常模糊，xml定義和示例不一致。還假定xml中的數據應該是不同的。

WITH src (bank, id, credit, info) AS (
    SELECT 1, 'A1', 'B1', 'C1' FROM dual UNION ALL 
    SELECT 1, 'A1', 'B1', 'C2' FROM dual UNION ALL 
    SELECT 1, 'A1', 'B1', 'C3' FROM dual UNION ALL 
    SELECT 1, 'A1', 'B2', 'D1' FROM dual UNION ALL 
    SELECT 1, 'A1', 'B2', 'D2' FROM dual UNION ALL 
    SELECT 1, 'A1', 'B1', 'C1' FROM dual UNION ALL 
    SELECT 2, 'X1', 'Y1', 'Z1' FROM dual 
), 
credit_data AS (
    SELECT 
     bank, 
     id, 
     XMLELEMENT("Credit", credit, 
      XMLAGG(
       XMLELEMENT(INFO, info) 
      ) 
     ) child_nodes 
    FROM 
     (SELECT DISTINCT * FROM src) 
    GROUP BY 
     bank, id, credit 
), 
bank_data AS (
    SELECT 
    XMLELEMENT("Bank", bank, 
     XMLELEMENT("ID", id, 
      XMLAGG(
       child_nodes 
      ) 
     ) 
    ) bank_nodes 
FROM 
    credit_data 
GROUP BY 
    bank, id 
) 
SELECT 
    XMLSERIALIZE(
     DOCUMENT 
     XMLELEMENT("Root", NULL, 
      XMLAGG(
       bank_nodes 
      ) 
     ) 
     INDENT SIZE = 2 
    ) xml 
FROM 
    bank_data;