所以這裏是我的代碼。否則如果錯誤
public static void play(Player player) {
Scanner localScanner = new Scanner(System.in);
while(localScanner.hasNextLine()){
String input = localScanner.nextLine();
if(input.equals("quit")) {
System.out.println("Game over, Good bye.");
return;
}
if(input.contains("north")){
buildWorld(player, player.moveTo().connectNorth());
} else if(input.contains("south")){
buildWorld(player, player.moveTo().connectSouth());
} else if(input.contains("east")){
buildWorld(player, player.moveTo().connectEast());
} else if(input.contains("west")){
buildWorld(player, player.moveTo().connectWest());
} else {
String contents;
if (!contents.equals(""))
System.out.println("There is:\n" + contents);
else{
System.out.println("This room is empty.");
} else if(input.startsWith("pickup")){ // <-- This is the 'orphan' else
contents = input.substring(8);
if(player.moveTo().moveTo(contents)){
Object localObject = player.connectWest(contents);
if(localObject !=null)
System.out.println("You have picked up " +localObject);
else
System.out.println("You have too much damage, Game over.");}
else {
System.out.println("There is no " +contents);
}} else if (input.startsWith("drop")){
contents=input.substring(6);
if(player.moveTo(contents))
System.out.println("you dropped " +contents);
else
System.out.println("You don't have "+ contents);
} else if(input.contains("status")){
System.out.println(player);}
else{
System.out.println("What?");}
}
}
}
我不斷收到一個沒有,如果錯誤,我不知道如何解決它。粗體代碼是發生錯誤的地方。我一直在研究這個問題好幾個小時,但我仍然無法完成這項工作。請,請幫助我。
使用標準的代碼格式會有所幫助。你的縮進和支架放置是非常隨機的,我們不能確定沒有閱讀所有的東西... – 2013-05-10 17:17:55
你只是**不能**做一個'else' -'sese if' – BackSlash 2013-05-10 17:18:27
其他的標準基本上是通用的在if-else鏈中。你不能有其他的 - 如果在它之後。 – Perception 2013-05-10 17:18:43