Rails 4. jQuery，Acts_as_list，嵌套模型，在控制器中更新位置

我想使用rails 4，acts_as_list gem和jQuery來對錶格中的項目（頁面）進行排序（scrape）。我認爲我的問題可能在控制器方法中，任何幫助都會非常感激。分類在前端很好地工作，trs完全像railscasts顯示的那樣上下移動。但它沒有更新的位置，刷新後，它回到它是如何。Rails 4. jQuery，Acts_as_list，嵌套模型，在控制器中更新位置

這裏是我的控制器方法排序

def sort 
    @scrape = Scrape.find(params[:scrape_id]) 
    @pages = @scrape.pages 

    @pages.each_with_index do |id, index| 
    Page.where(position: id).update_all({position: index+1}) 
    end 
    render nothing: true 
end

這是我的看法

= form_for @scrape do |f| 
    %p  
    = f.label :url 
    = f.text_field :website 

    %table#pages 
    %tbody{"data-update-url" => sort_scrape_pages_url(@scrape)} 
     = f.fields_for :pages, @pages do |page_type| 
     = content_tag_for :tr, page_type.object do 
      %td=page_type.object.position  

      %td    
      = link_to page_type.object.url, scrape_page_path(@scrape, page_type.object.id) 
      %td    
      = page_type.collection_select :page_type, ["Service Page", "Homepage","About Us", "Contact Us", "Informational", "Sitemap", "Privacy Policy", "Terms", "Blog"], :to_s, :humanize  
    = f.submit "Submit"

這裏是我的jQuery：

jQuery -> 
    $('#pages tbody').sortable 
    axis: 'y' 
    update: -> 
    $.post($(this).data('update-url'), $(this).sortable('serialize'))

而且這裏是我的控制檯說事，我dono如果這會幫助任何人，但在這裏。

Started POST "/scrapes/3/pages/sort" for 127.0.0.1 at 2015-04-19 18:28:56 -0700 
Processing by PagesController#sort as */* 
Parameters: {"page"=>["18", "17", "19", "20", "21", "22", "23", "24"], "scrape 
_pages_attributes_0"=>["id"], "scrape_pages_attributes_1"=>["id"], "scrape_pages 
_attributes_2"=>["id"], "scrape_pages_attributes_3"=>["id"], "scrape_pages_attri 
butes_4"=>["id"], "scrape_pages_attributes_5"=>["id"], "scrape_pages_attributes_ 
6"=>["id"], "scrape_pages_attributes_7"=>["id"], "scrape_id"=>"3"} 
Scrape Load (1.0ms) SELECT "scrapes".* FROM "scrapes" WHERE "scrapes"."id" = 
$1 LIMIT 1 [["id", "3"]] 
Page Load (1.0ms) SELECT "pages".* FROM "pages" WHERE "pages"."scrape_id" = $ 
1 ORDER BY position ASC [["scrape_id", 3]] 
    SQL (2.0ms) UPDATE "pages" SET "position" = 1 WHERE "pages"."id" = 17 
    SQL (1.0ms) UPDATE "pages" SET "position" = 2 WHERE "pages"."id" = 18 
    SQL (0.0ms) UPDATE "pages" SET "position" = 3 WHERE "pages"."id" = 19 
    SQL (0.0ms) UPDATE "pages" SET "position" = 4 WHERE "pages"."id" = 20 
    SQL (0.0ms) UPDATE "pages" SET "position" = 5 WHERE "pages"."id" = 21 
    SQL (0.0ms) UPDATE "pages" SET "position" = 6 WHERE "pages"."id" = 22 
    SQL (1.0ms) UPDATE "pages" SET "position" = 7 WHERE "pages"."id" = 23 
    SQL (0.0ms) UPDATE "pages" SET "position" = 8 WHERE "pages"."id" = 24 
Rendered text template (0.0ms) 
Completed 200 OK in 15ms (Views: 0.0ms | ActiveRecord: 6.0ms)

來源

2015-04-20 Blake Geist

錯誤是在我的控制器。我的工作排序方法如下。

def sort 
    params[:page].each_with_index do |id, index| 
    Page.where(id: id).update_all(position: index + 1) 
    end 
    render nothing: true 
end

來源

2015-04-20 14:30:24

您發現通過ID，它是錯誤的位置，但你需要通過ID查找記錄

所以你的方法，你需要更換你的代碼

@pages.each_with_index do |id, index| 
    Page.where(id: id).update_all(position: index + 1) 
end

來源

2015-04-20 06:04:22 SSR

謝謝@SSR，最後的調整讓它工作。（params [：page] .each_with_index do | id，index | Page.where（id：id）.update_all（position：index +1） end）' –

Rails 4. jQuery，Acts_as_list，嵌套模型，在控制器中更新位置

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