PHP數據沒有進入數據庫

-1

我想輸入某些數據到數據庫中，使用下面的html和php代碼......但顯然無論我在運行代碼時輸入到文本框中，輸入爲'1 '在數據庫中......我該如何解決這個問題？PHP數據沒有進入數據庫

<html> 
    <head> 
     <title>Project Details</title> 
    </head> 
    <body> 
     <?php include 'project.html'; 

     $pn=isset($_POST['name']) ? $_POST['ProjectName'] : ''; 
     $tn=isset($_POST['tname']) ? $_POST['TaskName'] : ''; 
    $dsc=isset($_POST['DESC']) ? $_POST['Proj_desc'] : ''; 
     $serverName = "Swagatha-PC"; 
     if($_SERVER['REQUEST_METHOD']=="POST") 
     { 
     $connectionInfo = array("Database"=>"Testing"); 
     $conn = sqlsrv_connect($serverName, $connectionInfo); 

    if($conn) 
      { 
echo "Connection established.<br />"; 
    } 
    else 
    { 
    echo "Connection could not be established.<br />"; 
    die(print_r(sqlsrv_errors(), true)); 
    } 

    $query="Insert Into dbo.Project (ProjectName,TaskName,Proj_desc) values ('$pn' ,'$tn' , '$dsc')"; 
     $stmt=sqlsrv_query($conn,$query); 


    if($stmt==false) 
     { 
    echo "Error in adding Info!! Reload Page an try again!!<br/>"; 
     die(print_r(sqlsrv_errors(), true)); 
     } 
    else 
    { 
    echo " Record Added!!"; 
    } 
    sqlsrv_close($conn); 

    } 
    ?> 
    </body> 
     </html>

和HTML代碼是

<html> 
    <head> 
     <title>Project Details</title> 
    </head> 
    <body> 
     <form method = "post" action = "http://localhost/project.php"> 
      <table> 
       <tr> 
        <td>Project Name:</td> 
        <td><input type = "text" name = "name"></td> 
       </tr> 
       <tr> 
        <td>Task Name:</td> 
        <td><input type = "text" name = "tname"></td> 
       </tr> 
       <tr> 
        <td>Project description:</td> 
        <td><textarea name = "DESC" rows = "5" cols = "40"></textarea></td> 
       </tr> 
       <tr> 
        <td><input type = "submit" name = "submit" value = "Submit" onclick="http://localhost/project.php"></td> 
       </tr> 
      </table> 
     </form> 
    </body> 
</html>

我輸入的數據被輸入這樣的數據庫： Output error

我怎樣才能解決這個錯誤????

來源

2017-01-11 Swagatha S

請更改

$pn=isset($_POST['ProjectName']); 
$tn=isset($_POST['TaskName']); 
$dsc=isset($_POST['Proj_desc']);

到

$pn=isset($_POST['name']) ? $_POST['name'] : ''; 
$tn=isset($_POST['tname']) ? $_POST['tname'] : ''; 
$dsc=isset($_POST['DESC']) ? $_POST['DESC'] : '';

來源

2017-01-11 03:16:12 laiju

在這樣空數據被插入到數據庫 –

Nope..It仍無法工作的 –

你可以重複查詢並粘貼輸出這裏 – laiju

PHP數據沒有進入數據庫

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