php通過電子郵件從數據庫中提取您的詳細信息

Question

我想創建一個文本字段和按鈕，允許用戶在文本字段中獲取他的詳細信息，而不是在每次他想進行新預訂時都寫下他的詳細信息。

像這樣的畫面： http://oi41.tinypic.com/23ie70j.jpg

我試圖使這一點，但我的代碼，但給我雙倍的形式之一與細節，一個沒有。

<form method="post" action="reserv page.php"> 
enter the email: <input type = "text" name = "email"/> 
<input type = "submit" name = "submit" value="submit" /> 
</form> 
<?php 
mysql_connect("localhost","userName","password"); 
mysql_select_db("database_Name"); 

if(isset($_POST['submit'])) 
{ 
$email = $_POST['email']; 
$q = "SELECT * FROM tabe WHERE the_email = '$email'"; 
$run = mysql_query($q); 

while($row = mysql_fetch_array($run)) 
{ 
?> 

</br></br> 

<form action="payment.php" method="post" > 
First Name:<input name="fName" type="text" value="<?php echo $row[1]; ?>" /> 
Last Name: <input name="lNamet" type="text" value="<?php echo $row[2]; ?>" /> 
User Name: <input name="uName" type="text" value="<?php echo $row[3]; ?>"/> 
Email:  <input name="email" type="text" value="<?php echo $row[4]; ?>" /> 
password: <input name="pass" type="password" value="<?php echo $row[5]; ?>"/> 
contact: <input name="number" type="text" value="<?php echo $row[6]; ?>" /> 

<input name="confirm" type="submit" value="Confirm" /> 
</form> 

</br></br> 

<?php 
}} 
?> 

<form action="payment.php" method="post" > 
First Name:<input name="fName" type="text" /> 
Last Name: <input name="lNamet" type="text" /> 
User Name: <input name="uName" type="text" /> 
Email:  <input name="email" type="text" /> 
password: <input name="pass" type="password" /> 
contact: <input name="number" type="text" /> 

<input name="confirm" type="submit" value="Confirm" /> 
</form> 

Answer 1

<form method="post" action="reserv page.php"> 
enter the email: <input type = "text" name = "email"/> 
<input type = "submit" name = "submit" value="submit" /> 
</form> 
<?php 
mysql_connect("localhost","userName","password"); 
mysql_select_db("database_Name"); 

if(isset($_POST['submit'])) 
{ 
    $email = $_POST['email']; 
    //limit the query to one entry :) 
    $q = "SELECT * FROM tabe WHERE the_email = '$email' LIMIT 1"; 
    $run = mysql_query($q); 

    //check if email is registered 
    if(mysql_num_rows($run)>0) 
    { 
     //display filled up form 
     while($row = mysql_fetch_array($run)) 
     { 
     ?> 

     </br></br> 

     <form action="payment.php" method="post" > 
     First Name:<input name="fName" type="text" value="<?php echo $row[1]; ?>" /> 
     Last Name: <input name="lNamet" type="text" value="<?php echo $row[2]; ?>" /> 
     User Name: <input name="uName" type="text" value="<?php echo $row[3]; ?>"/> 
     Email:  <input name="email" type="text" value="<?php echo $row[4]; ?>" /> 
     password: <input name="pass" type="password" value="<?php echo $row[5]; ?>"/> 
     contact: <input name="number" type="text" value="<?php echo $row[6]; ?>" /> 

     <input name="confirm" type="submit" value="Confirm" /> 
     </form> 

     </br></br> 

     <?php 
     } 
    } 
    //display blank form 
    else{ 
     ?> 

     <form action="payment.php" method="post" > 
     First Name:<input name="fName" type="text" /> 
     Last Name: <input name="lNamet" type="text" /> 
     User Name: <input name="uName" type="text" /> 
     Email:  <input name="email" type="text" /> 
     password: <input name="pass" type="password" /> 
     contact: <input name="number" type="text" /> 

     <input name="confirm" type="submit" value="Confirm" /> 
     </form> 
     <?php 
    } 
} 
?> 

Answer 2

你得到2種形式，因爲你是呼應一種形式，如果$_POST['submit']設置，然後又一個不顧一切了。只有在沒有設置$_POST['submit']時纔打印第二個表格。由於你的代碼寫得太差，我只給你一個例子：

if(isset($_POST['submit'])){ 
    PRINT FETCHED FORM 
}else{ 
    PRINT EMPTY FORM 
} 

但是，這不是「正確」的路要走。人們實際上做的是變量在開始時是空的，然後在數據中填充數據（如果有請求並在文件中寫入單個表單並將輸入值作爲這些變量）。