CF9 HQL語句對於很多一對多和多目標

Question

我有以下設置：

Listing.cfc

component persistent="true" 
{ 
    property name="ListingId" column="ListingId" type="numeric" ormtype="int" fieldtype="id" generator="identity"; 
     ... 
    property name="Features" type="array" hint="Array of features" singularname="Feature" fieldtype="many-to-many" cfc="Feature" linktable="Listing_Feature" FKColumn="ListingId" inversejoincolumn="FeatureId";  
} 

Feature.cfc

component persistent="true" table="Feature" schema="dbo" output="false" 
{ 
    property name="FeatureId" column="FeatureId" type="numeric" ormtype="int" fieldtype="id" generator="identity"; 
    property name="FeatureDescription" column="FeatureDescription" type="string" ormtype="string"; 
    ...  
    /*property name="Listings" fieldtype="many-to-many" cfc="Listing" linktable="Listing_Feature" fkcolumn="FeatureId" inversejoincolumn="ListingId" lazy="true" cascade="all" orderby="GroupOrder";*/ 

} 

我可以選擇的所有目錄有一個特殊的功能使用：

<cfset matchingListings = ormExecuteQuery("from Listing l left join l.Features as feature where feature.FeatureId = :feature",{feature = 110}) /> 

這很好，但是，我希望能夠選擇所有具有多個功能的列表（例如，同時具有「洗碗機」和「車庫」的列表）

經過幾個小時的谷歌搜索和通過hibernate文檔查看還沒有找到一個解決方案，不會給我一個錯誤。我的猜測是，解決方案非常簡單，我只是在想它...任何人有任何建議？

Answer 1

我不相信這是做到這一點的最有效的方法，但是，它會產生我想

<cfset matchingListings = ormExecuteQuery("Select l.ListingId from Listing l 
    left join l.Features as featureone left join l.Features as featuretwo 
    left join l.Features as featurethree 
    where featureone.FeatureId = 108 
    and featuretwo.FeatureId = 110 
    and featurethree.FeatureId = 113") /> 

結果這會給我只上市即擁有所有我找的功能，但它確實加盟，看着休眠SQL日誌的批生產：

select listing0_.ListingId as col_0_0_ 
from dbo.Listing listing0_ 
left outer join Listing_Feature features1_ on listing0_.ListingId=features1_.ListingId 
left outer join dbo.Feature feature2_ on features1_.FeatureId=feature2_.FeatureId 
left outer join Listing_Feature features3_ on listing0_.ListingId=features3_.ListingId 
left outer join dbo.Feature feature4_ on features3_.FeatureId=feature4_.FeatureId 
left outer join Listing_Feature features5_ on listing0_.ListingId=features5_.ListingId 
left outer join dbo.Feature feature6_ on features5_.FeatureId=feature6_.FeatureId 
where 1=1 
and feature2_.FeatureId=108 
and feature4_.FeatureId=110 
and feature6_.FeatureId=113 

這似乎只是必須有HQL

這樣做更有效的方式

---

喬恩·梅塞爾的CF-ORM-dev郵件列表上給了我什麼，我相信是最正確的解決這個問題張貼在這裏給大家：

「據我所知ORMExecuteQuery不處理列表參數，所以如果你想PARAM他們返回對象，你不得不這樣做

<cfset featureIds = [javaCast('int',108), javaCast('int',110), javaCast('int',113)] > 

<cfset q = ormGetSession().createQuery(" 
    select l.ListingId 
    from Listing l 
     join l.features as f 
    where f.FeatureId in (:features) 
    group by l.ListingId 
    having count(*) = #arrayLen(featureIds)# 
") /> 

<cfset q.setParameterList('features', featureIds) /> 

<cfset matchingListings = q.list() /> 

「

喬恩謝謝！

Answer 2

這應該工作：

<cfset featurelist = "110,113,125"/> 
<cfset matchingListings = ormExecuteQuery("from Listing l left join l.Features as feature where feature.FeatureId IN (#featurelist#)")/> 

如果你想要去的，你將不得不做一些額外的工作綁定參數，因爲Hibernate不喜歡ColdFusion的列表和/或數組作爲綁定參數這個時候。你可以找到一些額外的信息here