比較studentId首款然後studentSemester的
public class Student implements Comparable<Student> {
private int studentId;
private String studentName;
private int studentSemester;
public Student(int sId, String sName, int sSemester) {
this.studentId = sId;
this.studentName = sName;
this.studentSemester = sSemester;
}
public int getStudentId() {
return studentId;
}
public void setStudentId(int studentId) {
this.studentId = studentId;
}
public String getStudentName() {
return studentName;
}
public void setStudentName(String studentName) {
this.studentName = studentName;
}
public int getStudentSemester() {
return studentSemester;
}
public void setStudentSemester(int studentSemester) {
this.studentSemester = studentSemester;
}
@Override
public String toString() {
return "[" + studentId + ", " + studentName + ", " + studentSemester + "]";
}
@Override
public int compareTo(Student that) {
if(this.getStudentId() == that.getStudentId())
return 0;
if(this.getStudentSemester() > that.getStudentSemester())
return 1;
if(this.getStudentSemester() < that.getStudentSemester())
return -1;
return 0;
}
}
下面是測試類
import java.util.ArrayList;
import java.util.List;
import java.util.TreeSet;
public class MultipleOverrides {
public static void main(String args[]) {
Student s1 = new Student(1, "A", 1);
Student s2 = new Student(1, "A", 2);
Student s3 = new Student(1, "A", 3);
Student s4 = new Student(2, "B", 1);
Student s5 = new Student(2, "B", 2);
Student s6 = new Student(2, "B", 3);
Student s7 = new Student(3, "C", 1);
Student s8 = new Student(3, "C", 2);
Student s9 = new Student(3, "C", 3);
List<Student> students = new ArrayList<>();
students.add(s1);
students.add(s2);
students.add(s3);
students.add(s4);
students.add(s5);
students.add(s6);
students.add(s7);
students.add(s8);
students.add(s9);
System.out.println("All students before sorting : " + students);
TreeSet<Student> sortedStudents = new TreeSet<>();
sortedStudents.addAll(students);
System.out.println("All students after sorting : " + sortedStudents);
}
}
輸出:在排序前
所有的學生:[1,A, 1,A,2,[1,A,3],[2,B,1],[2,B,2],[2,B,3],[3, C,1],[3,C,2],[3,C,3]]
排序後的所有學生:[[1,A,1],[2,B,2],[ C,3]]
在覆蓋結束時,該方法應返回1而不是0,因爲0不允許任何其他具有相同學期的對象添加到樹中。 –