我有一個簡單的Web服務,它從數據庫抓取數據,並且我想將這些數據作爲數據集,字符串,XML返回。但Web服務XML沒有得到我返回的類型。問題是,是否有可能返回對象和Web服務XML來顯示正確的標記。目前它顯示這個標籤anytype而不是字符串例如。Web服務從方法返回匿名對象
這裏是方法
[WebMethod]
public Object serviceForPostcode(String postCode, String type)
{
/**
*
* create dataset to store query
* convert dataset to required return type
* create types for returned object
*
*
**/
SqlDataAdapter adapter = new SqlDataAdapter();
SqlCommand cmd = new SqlCommand();
SqlConnection conn = new SqlConnection(dbConnection());
/**
*
* -- types--
*
**/
XmlDocument xmlD = new XmlDocument();
StringWriter sw = new StringWriter();
DataSet dataSet = new DataSet();
/**
*
*
**/
// connection and query string
string dbQuery = "SELECT id, address1, address2, address3, address4, address5, post_code, country FROM paf WHERE (post_code = @postCode)";
try
{
cmd.Parameters.Add(new SqlParameter("@postcode",SqlDbType.NChar, 10)).Value = postCode.ToUpper();
cmd.CommandText = (dbQuery);
cmd.CommandType = CommandType.Text;
cmd.Connection = conn;
adapter.SelectCommand = cmd;
adapter.Fill(dataSet,"post codes");
}
catch(Exception e)
{
System.Web.HttpContext.Current.Response.Write(e.Message);
}
finally
{
//close database connection
conn.Close();
}
if (type.Equals("xml", StringComparison.InvariantCultureIgnoreCase))
{
return dataSet.GetXml();
}
else if (type.Equals("string", StringComparison.InvariantCultureIgnoreCase))
{
dataSet.WriteXml(sw);
return sw.ToString();
}
else if(type.Equals("dataset",StringComparison.InvariantCultureIgnoreCase))
{
return "";
}
return "error";
}
所以,你想一個方法,可以返回3種不同類型? – Pete