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我是一名PHP初學者。當我練習$_POST
時,我想發佈一個真實值,如日期1而不是鍵0.例如,當我選擇日期1並提交時,它將打印「您出生的日期1」而不是「您的出生日期0」由於數組鍵。我試過array_flip
但失敗了。任何人都不能幫助我嗎?如何發佈數組中的真值而不是PHP中的密鑰?
<html>
<body>
<?php
if(isset($_POST['submit'])){
$date = $_POST['Ngay'];
$month = $_POST['Thang'];
$year = $_POST['Nam'];
$gender = $_POST['Gender'];
$hidden = $_POST['hidden'];
echo "You born $date, $month, $year. Gender is $gender";
}
?>
<?php
function build_form($value){
foreach ($value as $k => $v){
echo "<option value = '{$k}'>".$v."</option>";
}
}
?>
<?php
$month = array(
1 => "Thang 1",
2 => "Thang 2",
3 => "Thang 3",
4 => "Thang 4",
5 => "Thang 5",
6 => "Thang 6",
7 => "Thang 7",
8 => "Thang 8",
9 => "Thang 9",
10 => "Thang 10",
11 => "Thang 11",
12 => "Thang 12",
);
$date = range(1,31) ;
$year = range(1990,2000);
?>
<form action="" method="post">
<select name = "Ngay">
<option>Choose date</option>
<?php
build_form($date);
?>
</select>
<select name = "Thang">
<option>Choose month</option>
<?php
build_form($month);
?>
</select>
<select name = "Nam">
<option>Choose year</option>
<?php
build_form($year);
?>
</select>
<select name = "Gender">
<option>Gender</option>
<option value="male">Male</option>
<option value="female">Female</option>
</select>
<input type="submit" name="submit" value="Submit">
<input type="hidden" name="hidden" value="id=1">
</form>
</body>
</html>
感謝您的支持:) –