我想使用C++使用TCP協議製作服務器和客戶端程序。服務器必須能夠一次處理多個客戶端。但問題是,例如,啓動服務器後,我運行2臺客戶端,並將服務器的IP地址和端口作爲參數。接下來,兩個客戶端都向服務器發送數據。起初,兩個客戶端都可以向服務器發送數據,服務器可以讀取數據。但是,一旦服務器從第二個客戶端收到數據,它似乎停止從第一個客戶端接收數據。你有任何解決方案?C++多客戶端TCP服務器
這裏是服務器端的代碼
using namespace std;
void *task1(void *);
static int connFd;
void error(const char *msg)
{
perror(msg);
exit(1);
}
int main(int argc, char* argv[])
{
int pId, portNo, listenFd;
socklen_t len; //store size of the address
bool loop = false;
struct sockaddr_in svrAdd, clntAdd;
pthread_t threadA[3];
if (argc < 2)
{
cerr << "Syntam : ./server <port>" << endl;
return 0;
}
portNo = atoi(argv[1]);
if((portNo > 65535) || (portNo < 2000))
{
cerr << "Please enter a port number between 2000 - 65535" << endl;
return 0;
}
//create socket
listenFd = socket(PF_INET, SOCK_STREAM, IPPROTO_TCP);
if(listenFd < 0)
{
cerr << "Cannot open socket" << endl;
return 0;
}
bzero((char*) &svrAdd, sizeof(svrAdd));
svrAdd.sin_family = AF_INET;
svrAdd.sin_addr.s_addr = INADDR_ANY;
svrAdd.sin_port = htons(portNo);
//bind socket
if(bind(listenFd, (struct sockaddr *)&svrAdd, sizeof(svrAdd)) < 0)
{
cerr << "Cannot bind" << endl;
return 0;
}
listen(listenFd, 5);
int noThread = 0;
while (noThread < 3)
{
socklen_t len = sizeof(clntAdd);
cout << "Listening" << endl;
//this is where client connects. svr will hang in this mode until client conn
connFd = accept(listenFd, (struct sockaddr *)&clntAdd, &len);
if (connFd < 0)
{
cerr << "Cannot accept connection" << endl;
return 0;
}
else
{
cout << "Connection successful" << endl;
}
pthread_create(&threadA[noThread], NULL, task1, NULL);
noThread++;
}
for(int i = 0; i < 3; i++)
{
pthread_join(threadA[i], NULL);
}
}
void *task1 (void *dummyPt)
{
cout << "Thread No: " << pthread_self() << endl;
char test[256];
bzero(test, 256);
bool loop = false;
while(!loop)
{
bzero(test, 256);
int n = read(connFd, test, 255);
if (n < 0) error("ERROR reading from socket");
printf("Here is the message: %s\n",test);
}
cout << "\nClosing thread and conn" << endl;
close(connFd);
}
而且客戶端代碼
using namespace std;
int main (int argc, char* argv[])
{
int listenFd, portNo;
bool loop = false;
struct sockaddr_in svrAdd;
struct hostent *server;
if(argc < 3)
{
cerr<<"Syntax : ./client <host name> <port>"<<endl;
return 0;
}
portNo = atoi(argv[2]);
if((portNo > 65535) || (portNo < 2000))
{
cerr<<"Please enter port number between 2000 - 65535"<<endl;
return 0;
}
//create client skt
listenFd = socket(PF_INET, SOCK_STREAM, IPPROTO_TCP);
if(listenFd < 0)
{
cerr << "Cannot open socket" << endl;
return 0;
}
server = gethostbyname(argv[1]);
if(server == NULL)
{
cerr << "Host does not exist" << endl;
return 0;
}
bzero((char *) &svrAdd, sizeof(svrAdd));
svrAdd.sin_family = AF_INET;
bcopy((char *) server -> h_addr, (char *) &svrAdd.sin_addr.s_addr, server -> h_length);
svrAdd.sin_port = htons(portNo);
int checker = connect(listenFd,(struct sockaddr *) &svrAdd, sizeof(svrAdd));
if (checker < 0)
{
cerr << "Cannot connect!" << endl;
return 0;
}
//send stuff to server
for(;;)
{
char s[300];
//cin.clear();
//cin.ignore(256, '\n');
cout << "Enter stuff: ";
bzero(s, 300);
cin.getline(s, 300);
write(listenFd, s, strlen(s));
}
}
你有一個答案,你原來的問題。試圖實現該答案會導致您獲得新的錯誤。您不應該通過添加錯誤來損害您的帖子,這些錯誤在仍處於帖子中的原始問題的上下文中是沒有意義的。相反,發佈錯誤的新問題。我已經編輯了這個問題,回答如何保持答案的完整性 – JBentley