如何調試使用基本身份驗證處理

Question

我正在使用urllib2和HTTPBasicAuthHandler像這樣的請求的urllib2要求：

import urllib2 

theurl = 'http://someurl.com' 
username = 'username' 
password = 'password' 

passman = urllib2.HTTPPasswordMgrWithDefaultRealm() 
passman.add_password(None, theurl, username, password) 

authhandler = urllib2.HTTPBasicAuthHandler(passman) 
opener = urllib2.build_opener(authhandler) 
urllib2.install_opener(opener) 

params = "foo=bar" 

response = urllib2.urlopen('http://someurl.com/somescript.cgi', params) 

print response.info() 

運行此代碼時，我目前得到一個httplib.BadStatusLine例外。我怎麼去調試？有沒有辦法查看原始響應是什麼，而不管無法識別的HTTP狀態碼？

Answer 1

您是否嘗試過在您自己的HTTP處理程序中設置調試級別？更改您的代碼是這樣的：

>>> import urllib2 
>>> handler=urllib2.HTTPHandler(debuglevel=1) 
>>> opener = urllib2.build_opener(handler) 
>>> urllib2.install_opener(opener) 
>>> resp=urllib2.urlopen('http://www.google.com').read() 
send: 'GET/HTTP/1.1 
     Accept-Encoding: identity 
     Host: www.google.com 
     Connection: close 
     User-Agent: Python-urllib/2.7' 
reply: 'HTTP/1.1 200 OK' 
header: Date: Sat, 08 Oct 2011 17:25:52 GMT 
header: Expires: -1 
header: Cache-Control: private, max-age=0 
header: Content-Type: text/html; charset=ISO-8859-1 
... the remainder of the send/reply other than the data itself 

所以三行預先考慮是：

handler=urllib2.HTTPHandler(debuglevel=1) 
opener = urllib2.build_opener(handler) 
urllib2.install_opener(opener) 
... the rest of your urllib2 code... 

，將顯示在stderr原始HTTP發送/應答循環。從評論

編輯工作的呢？

... same code as above this line 
opener=urllib2.build_opener(authhandler, urllib2.HTTPHandler(debuglevel=1)) 
... rest of your code