使用與= ANY

Question

查詢的CTE：

WITH first_names AS (SELECT DISTINCT fname FROM voters) 
SELECT name 
from nicknames 
WHERE groupi = (
    SELECT nn.groupi 
    FROM nicknames AS nn 
    WHERE name = 'john' 
) AND name != 'john' AND upper(name) = ANY(first_names); 

錯誤： column "first_names" does not exist

如何使一個數組從選擇，並在那裏語句中使用它？

Answer 1

你在這裏混淆輔助語句指定的列。 first_names是您的SELECT DISTINCT提供的結果的名稱，而fname是其中包含的列的名稱。

不對整個查詢的正確性發表評論，更正的語句將使用正確的列名稱。

WITH first_names AS (SELECT DISTINCT fname 
        FROM voters) 
SELECT name 
FROM nicknames 
WHERE groupi = (
    SELECT nn.groupi 
    FROM nicknames AS nn 
    WHERE name = 'john' 
) AND name != 'john' AND upper(name) = ANY (first_names.fname); 

Answer 2

try JOIN instead of ANY

WITH first_names AS (SELECT DISTINCT fname FROM voters) 
SELECT name 
from nicknames 
JOIN first_names on fname = upper(name) 
WHERE groupi = (SELECT nn.groupi FROM nicknames AS nn WHERE name = 'john') AND name != 'john' 
;