我的代碼的縮進

Question

我寫過我的程序從命令行獲取參數並使用文件中的數字生成一堆統計數據。由於存在縮進錯誤，我無法編譯我的代碼。我試過了，但我只是看不到我的縮進不正確。有人能指出我正確的方向嗎？

代碼：

import sys 

def median(alist): 
    n=len(alist) 
    if n<1: 
     return 'There are none' 
    if n%2: 
     return sorted(alist)[n//2] 
    else: 
     return sum(sorted(alist)[n//2-1:n//2+1])/2.0 

def minimum(alist): 
    return min(alist) 

def maximum(alist): 
    return max(alist) 

def average(alist): 
    return sum(alist)/len(alist) 

def main(): 
    with open(sys.argv[1], 'r') as handle: 
    lines = handle.readlines() 
    list1 = [] 
    for line in lines: 
     fields = line.split() 
    for field in fields: 
     list1.append(float(field)) 
    median(alist) 
    minimum(alist) 
    maximum(alist) 
    average(alist) 

if __name__ == '__main__': 
    main() 

錯誤：需要後with語句縮進

File "stats.py", line 23
lines = handle.readlines()
^
IndentationError: expected an indented block

Answer 1

您的代碼。這是正確的代碼。

import sys 

def median(alist): 
    n=len(alist) 
    if n<1: 
     return 'There are none' 
    if n%2: 
     return sorted(alist)[n//2] 
    else: 
     return sum(sorted(alist)[n//2-1:n//2+1])/2.0 

def minimum(alist): 
    return min(alist) 

def maximum(alist): 
    return max(alist) 

def average(alist): 
    return sum(alist)/len(alist) 

def main(): 
    with open(sys.argv[1], 'r') as handle: 
     lines = handle.readlines() 
    list1 = [] 
    for line in lines: 
     fields = line.split() 
    for field in fields: 
     list1.append(float(field)) 
    median(alist) 
    minimum(alist) 
    maximum(alist) 
    average(alist) 

if __name__ == '__main__': 
    main() 

Answer 2

您縮進應該是一致的，雖然出腳本 佩普8強recomends標籤上使用的空間。 我個人使用4個空格

由於JonDoe已經縮進上面說的與語句需要爲做縮進，而之後，if語句