2016-06-30 118 views
0

curently我在我的項目中使用Hibernate與MS SQL 2008。 我想在hibernate中執行存儲過程。下面 是SP:休眠與MS SQL存儲過程

SET ANSI_NULLS ON 
GO 
SET QUOTED_IDENTIFIER ON 
GO 
ALTER PROCEDURE [dbo].[GetUserDetails] (@userId int) 
AS 
BEGIN 
    SELECT * FROM dcf_user_m WHERE nuserid = @userId; 
END 

Exec dbo.GetUserDetails @userId=14 

下面是執行休眠代碼。

Session session = transactionManager.getSessionFactory().getCurrentSession(); 
     Transaction transaction = session.getTransaction(); 
     if(!transaction.isActive()){ 
      session.beginTransaction(); 
     } 

     Query query = session.createSQLQuery("Exec dbo.GetUserDetails @userId=:userId").setParameter("userId", 14);   
      List result = query.list(); 

      for(int i=0; i<result.size(); i++){ 
       com.majesco.msig.entity.UserInfo user = (com.majesco.msig.entity.UserInfo)result.get(i); 
       System.out.println(user.getUsername()); 
      } 

query.list()我越來越低的錯誤。

INFO: Reloading Context with name [/msig] is completed 
Hibernate: Exec dbo.GetUserDetails @userId=? 
org.hibernate.MappingException: No Dialect mapping for JDBC type: -9 
    at org.hibernate.dialect.TypeNames.get(TypeNames.java:76) 
    at org.hibernate.dialect.TypeNames.get(TypeNames.java:99) 
    at org.hibernate.dialect.Dialect.getHibernateTypeName(Dialect.java:592) 

如何解決此問題,請幫助。提前致謝 !!!

回答

0

另一種猜測:-),嘗試添加實體信息

Query query = session 
    .createSQLQuery("Exec dbo.GetUserDetails @userId=:userId") 
    .addEntity(UserInfo.class) 
    .setParameter("userId", 14);   

採取from here

+0

感謝您的回覆,嘗試過這個,但同樣的錯誤... –

+0

我有另一個建議,仍然猜測我害怕。 –