調用表達下探雙引號

Question

我有一個zip文件的目錄結構，它 ，我想用一個腳本來提取他們 我的劇本至今

$7zexe = "c:\bin\7za.exe" 
$arg = "" 
Get-ChildItem -Recurse -Include *.zip | 
ForEach-Object { $argout = $_.Directory.Name 
    $arg = " e `"$_`" -o`"$argout`"" 
    $cmdline = $7zexe, $arg -join "" 
    $cmdline 
    Invoke-Expression -command "$cmdline " 
} 

，但我得到以下錯誤

c:\bin\7za.exe e "E:\tmp\the folder\the sub folder\my_big_file.zip" -o"the sub folder" 
Invoke-Expression : The string starting: 
At line:1 char:86 
+ c:\bin\7za.exe e "E:\tmp\the folder\the sub folder\my_big_file.zip" -o"the sub folder <<<< " 
is missing the terminator: ". 
At x:\mydocs\testscript.ps1:9 char:18 
+ Invoke-Expression <<<< -command "$cmdline " 
    + CategoryInfo   : ParserError: (:String) [Invoke-Expression], IncompleteParseException 
    + FullyQualifiedErrorId : TerminatorExpectedAtEndOfString,Microsoft.PowerShell.Commands.InvokeExpressionCommand 

不知怎的，它看起來像PowerShell是下降我收「

我與& OPER試了一下ator和我也嘗試用數組替換參數

[Array]$arg = "e ", "`"$_`""," -o`"$argout`"" 

任何暗示讚賞！

Answer 1

儘量把-o引號內：

$7zexe = "c:\bin\7za.exe" 
$arg = "" 
Get-ChildItem -recurse -Include *.zip | 
ForEach-Object { $argout = $_.Directory.FullName 
    write-host -ForegroundColor Green $argout 
    $arg = " e `"$_`" `"-o$argout`"" 
    $cmdline = $7zexe, $arg -join "" 
    $cmdline 
    Invoke-Expression -command "$cmdline " 
} 

旁註：要確保一個深度嵌套壓縮文件中的內容被解壓縮到正確的目錄，我相信你應該使用FullName屬性包含的目錄。