如何找出循環在foreach循環中每條條件執行多少次？

Question

嘿，我需要你的幫助，這個練習。

我有這樣的陣列，我需要打印出各正，負，零數，然後後，我需要打印出號碼的數量在例如每個進程的正數計數是2

你能幫我做這個嗎？

全碼：

<style> 
 
    body { 
 
     background: #333; 
 
    } 
 
</style> 
 

 
<?php 
 

 
$numbers = [10, 20, -20, -30, 0, 0, 0]; 
 
echo "<ul>"; 
 

 
foreach ($numbers as $number) { 
 
    if ($number > 0) { 
 
     echo "<li style='color: #080;'>Positive Number : {$number}</li><br />"; 
 
    } elseif ($number == 0) { 
 
     echo "<li style='color: #FF0;'>Zero Number : {$number}</li><br />"; 
 
    } elseif ($number) { 
 
     echo "<li style='color: #F00;'>Negative Number : {$number}</li><br />"; 
 
    } 
 
} 
 
echo "</ul>";

謝謝你們

Answer 1

創建一個計數器。

<style> 
    body { 
     background: #333; 
    } 
</style> 

<?php 

$numbers = [10, 20, -20, -30, 0, 0, 0]; 
$counts = [0,0,0]; //positive,negative,zero 
echo "<ul>"; 

foreach ($numbers as $number) { 
    if ($number > 0) { 
$counts[0]++; 
     echo "<li style='color: #080;'>Positive Number : {$number}</li><br />"; 
    } elseif ($number == 0) { 
$counts[2]++; 
     echo "<li style='color: #FF0;'>Zero Number : {$number}</li><br />"; 
    } else { 
$counts[1]++; 
     echo "<li style='color: #F00;'>Negative Number : {$number}</li><br />"; 
    } 
} 
// access here 
echo "</ul>"; 

Answer 2

您必須聲明計數器變量並在if條件中增加它們。

<style> 
    body { 
     background: #333; 
    } 
</style> 

<?php 

$numbers = [10, 20, -20, -30, 0, 0, 0]; 
echo "<ul>"; 

$positiveNumbers = 0; 
$negativeNumbers = 0; 
$zeros = 0; 

foreach ($numbers as $number) { 
    if ($number > 0) { 
     $positiveNumbers++; 
     echo "<li style='color: #080;'>Positive Number : {$number}</li><br />"; 
    } elseif ($number == 0) { 
     $zeros++; 
     echo "<li style='color: #FF0;'>Zero Number : {$number}</li><br />"; 
    } else { 
     $negativeNumbers++; 
     echo "<li style='color: #F00;'>Negative Number : {$number}</li><br />"; 
    } 
} 
echo "</ul>"; 
echo "Total Positive Numbers: $positiveNumbers<br/>"; 
echo "Total Negative Numbers: $negativeNumbers<br/>"; 
echo "Total Zeroes: $zeros<br/>"; 

Answer 3

如果你只是想在陣列中的負，正和零Ø打印總數，你可以做到這一點，如下：

<style> 
    body { 
     background: #333; 
    } 
</style> 

<?php 

$numbers = [10, 20, -20, -30, 0, 0, 0]; 
$totalPositive = 0; $totalNegative = 0; $totalZero = 0; 

echo "<ul>"; 

//Firstly count the number of positive, negative and zero 
foreach ($numbers as $number) { 
    if ($number > 0) { 
     $totalPositive++; 
    } elseif ($number == 0) { 
     $totalZero++; 
    } else { 
     $totalNegative++; 
    } 
} 
//print them all 
echo "<li style='color: #080;'>Positive Number : {$totalPositive}</li><br />"; 
echo "<li style='color: #FF0;'>Zero Number : {$totalZero}</li><br />"; 
echo "<li style='color: #F00;'>Negative Number : {$totalNegative}</li><br />"; 
echo "</ul>";