重塑你的數據如下,假設列名,name
,並value
:
training.data.raw <- data_frame(name = c("IN", "IS", "IT", "JO", "JP", "KZ", "MA", "MZ", "NG", "NO", "NZ", "PE", "PH", "PR", "RO", "RU", "SA", "SE", "SY", "TM", "TN", "TR", "UK", "US", "WS"),
value = c(999, 1, 1885, 1098, 2, 584, 858, 11, 10, 522, 193, 29, 2, 1, 1603, 353, 6, 2, 4, 33, 228, 3201, 852, 1363, 1));
可以使用top_n
功能在dplyr
包輕鬆地獲得您想要的結果(在幫助文件?top_n
詳細信息):
library(dplyr);
top_3 <- top_n(x=training.data.raw, n=3);
top_3;
編輯基於註釋:如果你有性格的因素,而不是常規的特徵向量,可以先mutate
他們的字符:
training.data.characters <- mutate(training.data.raw, name = as.character(name));
# Now top_n() will take it
# Can also explicity state wt argument to tell it to sort by value
top_3 <- top_n(x=training.data.characters, n=3, wt=value);
top_3;
謝謝,但我收到此消息 '錯誤UseMethod(「tbl_vars」): 沒有適用於'tbl_vars'適用於類「factor」類對象的方法 –
好吧,這意味着您的命名變量是'因素'。這是尷尬的。你可以先用'mutate'變換它們。我會更新答案。 –
謝謝!我會檢查出來 –