Python中的文件內的字符串比較

Question

我需要在python中編寫腳本來查找第7行的輸出，如果第一行爲真（6c00ff00 = 1），則輸出爲「y」。我能夠捕獲文件中的所有這些值（比如「xyz」），但我無法在文件中進行比較。

>>> vi xyz 

6c00ff00 = 1 
6c01ff00 = BGSV 1 
6c02ff00 = 08IS01191025 
6c03ff00 = 192.11.13.5 
7005ff00 = g430 
e808ff00 = 249 
6c0aff00 = y 
7002ff00 = 35 .4 .0/
7001ff00 = 0 
7b00ff00 = 
7100ff00 = 1 
7003ff00 = 192.11.13.150 

Answer 1

with open('xyz') as infile: 
    line1 = infile.readline().strip() 
    for _ in xrange(6): 
    line7 = infile.readline() 
    line7 = line7.strip() 
    print "The first line is '%s'" %line1 
    print "The seventh line is '%s'" %line7 
    if line1.split('=')[1].strip() == '1': 
    if line7.split('=')[1].strip() == 'y': 
     print "Correct" 
    else: 
     print "Wrong"