2014-01-14 38 views

回答

0

像這可能是有用的函數:

function GetUrl() { 
    var ss = SpreadsheetApp.getActiveSpreadsheet(); 
    return ss.getUrl(); 
} 

enter image description here

檢查:Class Spreadsheet - getUrl()

+0

完美,謝謝! – TobiasH

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