2013-07-16 14 views
2

我有一個Python列表創建字典:如何從一個特定的Python列表

[('Three', 8), ('Nine', 9), ('Two', 4), ('Two', 5), ('One', 0), ('One', 1), ('One', 6)] 

,我想創建一個Python字典:

{ 'One', [0,1,6], 'Two':[4,5], 'Three':[8], 'Nine':[9] } 

我怎樣才能做到這一點用列表解析?我試圖用屬於同一字符串值的數字創建列表,但我不知道如何在列表理解中動態創建列表。

回答

6

只需使用常規for循環:

from collections import defaultdict 

d = defaultdict(list) 

for key, value in your_list: 
    d[key].append(value) 
1

,我會用defaultdict但如果你真的想與理解發揮,你可以嘗試

{k : [v for kk, v in l if k == kk] for k in set(i for i, _ in l)} 
{'Nine': [9], 'One': [0, 1, 6], 'Three': [8], 'Two': [4, 5]} 

我不會推薦它,以提高效率和可讀性原因。

0
>>> from operator import itemgetter as get 
>>> from itertools import groupby as gb 
>>> l = [('Three', 8), ('Nine', 9), ('Two', 4), ('Two', 5), ('One', 0), ('One', 1), ('One', 6)] 

>>> {k: zip(*list(v))[1] for k,v in gb(sorted(l), get(0))} 
{'Two': (4, 5), 'Nine': (9,), 'Three': (8,), 'One': (0, 1, 6)} 
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