在ListView中切分頁？

Question

我已成功將分頁添加到list_contacts視圖（顯然是爲聯繫人模型）。而我現在想安裝模板背景下，這樣我可以限制分頁顯示，看起來像這樣：

< 1 ... 5 6 7 8 9 ... 42 > 

我從this answer去，並試圖用「分頁程序」模板標籤，沒有成功。主要問題是我使用的是ListView而不是舊的object_list，而這兩者並沒有以相同的方式設置上下文。

這是我的觀點：

from django.views.generic import ListView 
from app.models import Contact 

list_contacts = ListView.as_view(
     model=Contact, 
     http_method_names = ['get'], 
     template_name='contacts.html', 
     context_object_name='contacts', 
     paginate_by=6 
     ) 

而且我的模板 「contacts.html」：

<ul class="pagination"> 
    {# Previous page link #} 
    {% if page_obj.has_previous %} 
    <li> 
     <a href="?page={{ page_obj.previous }}">&laquo;</a> 
    </li> 
    {% else %} 
    <li class="disabled"> 
     <a href="#">&laquo;</a> 
    </li> 
    {% endif %} 

    {# First page #} 
    {% if show_first %} 
    <li> 
     <a href="?page=1">1</a> 
    </li> 
    <li>...</li> 
    {% endif %} 

    {# List of pages (with current "active") #} 
    {% for page in page_numbers %} 
    {% ifequal page page_obj.number %} 
    <li class="active"> 
     <a href="#">{{ page }}</a> 
    </li> 
    {% else %} 
    <li> 
     <a href="?page={{ page }}">{{ page }}</a> 
    </li> 
    {% endifequal %} 
    {% endfor %} 

    {# Last page #} 
    {% if show_last %} 
    <li>...</li> 
    <li><a href="?page=last">{{ page_obj.pages }}</a></li> 
    {% endif %} 

    {# Next page link #} 
    {% if page_obj.has_next %} 
    <li> 
     <a href="?page={{ page_obj.next_page_number }}">&raquo;</a> 
    </li> 
    {% else %} 
    <li class="disabled"> 
     <a href="#">&raquo;</a> 
    </li> 
    {% endif %} 
</ul> 

編輯：下面是結束了我的視圖代碼工作

class ListContactsView(ListView): 
    model = Contact 
    http_method_names = ['get'] 
    template_name = 'contacts.html' 
    context_object_name = 'contacts' 
    paginate_by = 6 

    def get_context_data(self, **kwargs): 
     _super = super(ListContactsView, self) 
     context = _super.get_context_data(**kwargs) 
     adjacent_pages = 2 
     page_number = context['page_obj'].number 
     num_pages = context['paginator'].num_pages 
     startPage = max(page_number - adjacent_pages, 1) 
     if startPage <= 3: 
      startPage = 1 
     endPage = page_number + adjacent_pages + 1 
     if endPage >= num_pages - 1: 
      endPage = num_pages + 1 
     page_numbers = [n for n in xrange(startPage, endPage) \ 
       if n > 0 and n <= num_pages] 
     context.update({ 
      'page_numbers': page_numbers, 
      'show_first': 1 not in page_numbers, 
      'show_last': num_pages not in page_numbers, 
      }) 
     return context 
list_contacts = ListContactsView.as_view() 

Answer 1

有不同的方式來實現這一點（甚至是一些組合）：

1. 覆蓋或通過調用超
2. 延伸get_context_data寫templatetag
3. 寫模板濾波器
4. 覆蓋或擴展的PaginationMixin

第一

class MyListView(ListView): 
    def get_context_data(self, **kwargs): 
     context = super(MyListView, self).get_context_data(**kwargs) 
     context['foo'] = 'bar' 
     return context