填充隨機數值的長短整型數組

Question

我在使用隨機數發生器填充長整型數組和短整型隨機數字時遇到了問題。我可以用double和float類型的數組來做到這一點，但是對其他兩個類型沒有好運。我所提出的代碼只打印出數組中所有10個元素的1。

const int size = 10; 
short int* myShorts = new short[size]; 
long int* myLongs = new long[size]; 
... 
... 
// short fill 
std::cout << "Short Array: \n"; 
for (int i = 0; i < size; i++) 
{ 
    *(myShorts + i) = rand()/short(RAND_MAX)*50.f + 1.f; 
    std::cout << i << ": " << std::setprecision(4) << *(myShorts + i) << std::endl; 
} 

// long fill 
std::cout << "Long Array: \n"; 
for (int i = 0; i < size; i++) 
{ 
    *(myLongs + i) = rand()/long(RAND_MAX)*50.f + 1.f; 
    std::cout << i << ": " << std::setprecision(4) << *(myLongs + i) << std::endl; 
} 

我的結果是這樣的：

Short Array: 
0: 1 
1: 1 
2: 1 
3: 1 
4: 1 
5: 1 
6: 1 
7: 1 
8: 1 
9: 1 

Long Array: 
0: 1 
1: 1 
2: 1 
3: 1 
4: 1 
5: 1 
6: 1 
7: 1 
8: 1 
9: 1 

Answer 1

可能：

*(myLongs + 1) = (float)rand()/(float)RAND_MAX * 50.f + 1.f; 

？