如何從點擊的JOptionPane選項獲取輸入。 - java的

Question

我怎樣才能得到被點擊了JOptionPane從選項中輸入，而不是Okay按鈕，但我已經提供了諸如Emerald的選項，Autumn等

這裏是我的代碼

public static ArrayList<String> Skins = new ArrayList<String>(); 

public static void skinJPanel() { 
    try { 
     String[] skins = {"Emerald", "Autumn", "Black Steel", "Blue Steel", "Creme Coffee", "Green Magic"}; 
     for (int i = 0; i <= 5; i++) { 
      Skins.add(skins[i]); 
     } 
     JPanel panel = new JPanel(); 
     panel.setSize(200, 200); 
     JList list = new JList(Skins.toArray()); 
     JScrollPane scrollpane = new JScrollPane(); 
     scrollpane = new JScrollPane(list); 
     panel.add(scrollpane); 
     scrollpane.getViewport().add(list); 
     String string = JOptionPane.showInputDialog(null, scrollpane, "Aftermath Skin Chooser", JOptionPane.PLAIN_MESSAGE); 
     System.out.println(string); 
    } catch (Exception e) { 
     e.printStackTrace(); 
    } 
    Skins.clear(); 
} 

Answer 1

要獲得選定的值在用戶按下[好]之後，您應該做更多的事情......

int result = JOptionPane.showConfirmDialog(null, scrollpane, "Aftermath Skin Chooser", JOptionPane.OK_CANCEL_OPTION, JOptionPane.PLAIN_MESSAGE); 
if (result == JOptionPane.OK_OPTION) { 
    String value = (String) list.getSelectedValue(); 
    System.out.println(value); 
}