翻譯JPA查詢謂詞彈簧數據規範

Question

我需要此JPA查詢翻譯成一個謂詞（用於彈簧數據規範）：

select v.id from VideoImpl v , in (v.assetSet.publishings) as p where p.channelId='23FFBE1B-65CE-4188-ADD2-C724186C2C9F' 

其中assetSet是多對一和publishings一個一對多關係

Hibernate生成的SQL是這樣的：

select videoimpl0_.id as col_0_0_ from Video videoimpl0_ inner join Asset videoimpl0_1_ on videoimpl0_.id=videoimpl0_1_.id inner join AssetSet assetsetim1_ on videoimpl0_1_.assetSetId=assetsetim1_.id left outer join AssetSet_Image assetsetim1_1_ on assetsetim1_.id=assetsetim1_1_.assetSetId inner join Publishing publishing2_ on assetsetim1_.id=publishing2_.assetSetId where publishing2_.channelId='23FFBE1B-65CE-4188-ADD2-C724186C2C9F' 

任何人有線索？

Answer 1

最後它很容易做到。我專注於生成的sql，而不是用（*）多選表達式中不熟悉的jpa查詢。所以這個作品：

private static <T> Predicate appendPublishingChannelIdCondition(Predicate predicate, ExpressionCache<T> cache, CriteriaBuilder cb, CriteriaQuery<?> query, String channelId) { 
    Subquery<String> publishingSubquery = query.subquery(String.class); 
    Root<PublishingImpl> publishingRoot = publishingSubquery.from(PublishingImpl.class); 
    Predicate channelPredicate = cb.equal(publishingRoot.get("channelId"), channelId); 
    Subquery<String> assetSetId = publishingSubquery.select(publishingRoot.<String>get("assetSetId")).where(channelPredicate); 
    Path attributePath = cache.getAttributePath("assetSet"); 
    return cb.and(predicate, attributePath.in(assetSetId)); 
}